help with swich cases

I want to have my users of my programs to have the choice to start over by pressing y for yes and n for no, also, after it get results, u must press enter again for the optains to appear


Heres part of the code

Code:

---

int cels(){
 
  float x; 
  cout << "Temperature Celsius:";
  cin>> x;
  cin.ignore();
  cout << "Fahrenheit:" << cel (x);
  cin.get();
 int input3;
  cout<<"Start over 1.yes / 2.no :\n";
  cin>> input3;
  switch ( input3 ) {
  case 1:           
    main();
    break;
  case 2:           
    cout:"/n";
    break;
  default:           
    cout<<"Error\n";
    break;
  }
 }

---

i had to have yes and no be choesen by 1 or 2

I don't see what you're asking?

Look, ive posted this code b4, but i want to b able to restart it by pressing y intstead of 1 or 2

Code:

---

#include <iostream>

float far ( float x )
{
 return (x-32)*(5.0/9.0);
}

float cel ( float x )
{
 return (x*1.8)+32;
}

using namespace std;

int faren();

int cels();

int main ()
{
  int input;
 
  cout<<"1. Celsius to Fahrenheit\n";
  cout<<"2. Fahrenheit to Celsius\n";
  cout<<"Selection: ";
  cin>> input;
  switch ( input ) {
  case 1:           
    cels();
    break;
  case 2:           
    faren();
    break;
  default:           
    cout<<"Error\n";
    break;
  }
}

int faren() {
 
  float x; 
  cout << "Temperature Farenhieht:";
  cin >> x;
  cin.ignore();
  cout << "Celsius:" << far(x);
  cin.get();
 
int input2;
cout<<"Start over 1.yes / 2.no :\n";
  cin>> input2;
  switch ( input2 ) {
  case 1:           
    main();
    break;
  case 2:           
    cout:"/n";
    break;
  default:           
    cout<<"Error\n";
    break;
  }
}
 
int cels(){
 
  float x; 
  cout << "Temperature Celsius:";
  cin>> x;
  cin.ignore();
  cout << "Fahrenheit:" << cel (x);
  cin.get();
 int input3;
  cout<<"Start over 1.yes / 2.no :\n";
  cin>> input3;
  switch ( input3 ) {
  case 1:           
    main();
    break;
  case 2:           
    cout:"/n";
    break;
  default:           
    cout<<"Error\n";
    break;
  }
 }

---

Then instead of

case 1 : ....

you want

case 'y' : ....

Oops, you'll also want to make sure the input variable is a char.

I did that and it gives me an error of 'y' undeclaired ( first use this fuction) and

'n' undeclaired ( first use this fuction)


i didnt do that, well i tried case char and just char, but it gave me even more errors

I had to.. edit.. this. Recursive calls to main() are bad, as were a few other things. ;)

Code:

---

#include <iostream>

int menu();
float far(float x);
float cel(float x);

bool quitflag = 0;

int main()
{
    while (quitflag != 1)
    {
        menu();
    }
     
    return(0);
}

int menu()
{
    int ans;
    char again;
 
    std::cout << "1. Celsius to Fahrenheit";
    std::cout << "\n2. Fahrenheit to Celsius";
 
    std::cout << "\n\nSelection: ";
    std::cin >> ans;
   
    if (ans == 1)
    {
        int temp = 0;
       
        std::cout << "\nTemperature: ";
        std::cin >> temp;
       
        std::cout << "\nFinal temp is: " << cel(temp);
    }
    else if (ans == 2)
    {
        int temp = 0;
       
        std::cout << "\nTemperature: ";
        std::cin >> temp;
       
        std::cout << "\nFinal temp is: " << far(temp);
    }
    else
    {
        std::cout << "\nInvalid input, please try again.\n\n";
        return(0);
    }
   
    std::cout << "\n\nCalculate another? ";
    std::cin >> again;
    std::cout << std::endl;
   
    tolower(again);
       
    if (again == 'n') // Only need to test an 'n' condition, the rest will auto-repeat. Switch this to 'y' and take out the 'quitflag' line if you want it to exit on anything except 'y'.
    {
        quitflag = 1;
        return(0);
    }
   
    return(0);
           
}

float far(float x)
{
    return((x-32)*(5.0/9.0));
}

float cel(float x)
{
    return((x*1.8)+32);
}

---

Quote:

---

error of 'y' undeclaired ( first use this fuction)

---

Did your case statements say (for example) case y: or were they properly case 'y': ? There's a big difference.

my bad, i used that first one

I got it working

Code:

---

#include <iostream>

float far ( float x )
{
 return (x-32)*(5.0/9.0);
}

float cel ( float x )
{
 return (x*1.8)+32;
}

using namespace std;

int faren();

int cels();

int main ()
{
  int input;
 
  cout<<"1. Celsius to Fahrenheit\n";
  cout<<"2. Fahrenheit to Celsius\n";
  cout<<"Selection: ";
  cin>> input;
  switch ( input ) {
  case 1:           
    cels();
    break;
  case 2:           
    faren();
    break;
  default:           
    cout<<"Error\n";
    break;
  }
}

int faren() {
 
  float x; 
  cout << "Temperature Farenhieht:";
  cin >> x;
  cin.ignore();
  cout << "Celsius:" << far(x);
  cin.get();
 
char input2;
cout<<"Start over y / n :\n";
  cin>> input2;
  switch ( input2 ) {
  case 'y':           
    main();
    break;
  case 'n':           
    cout:"/n";
    break;
  default:           
    cout<<"Error\n";
    break;
  }
}
 
int cels(){
 
  float x; 
  cout << "Temperature Celsius:";
  cin>> x;
  cin.ignore();
  cout << "Fahrenheit:" << cel (x);
  cin.get();
 char input3;
  cout<<"Start over y / n :\n";
  cin>> input3;
  switch ( input3 ) {
  case 'y':           
    main();
    break;
  case 'n':           
    cout:"/n";
    break;
  default:           
    cout<<"Error\n";
    break;
  }
 }

---

Ok but i still have one problem, the user must press return to get the y / n option. I know it is a really easy thing, but i cant figure it out

Quote:

---

Code:

---

if (again == 'n') // Only need to test an 'n' condition, the rest will auto-repeat. Switch this to 'y' and take out the 'quitflag' line if you want it to exit on anything except 'y'.
    {
        quitflag = 1;
        return(0);
    }
   
    return(0);

---

---

What's quitflag

quitflag is a boolian variable that is either FALSE (0) or TRUE (1). Since I am using a while() that keeps you in the menu until the user quits, I can say this:

WHILE quitflag IS false
ENTER menu() function

Then, when the user types N or n, I make 'quitflag' true. The while loop evaluates false, and the program exits.

read his code, it's very simple

With a little common sense, you could do a search (CTRL+F) to see where else he uses that variable. Oh, surely enough - he has a while loop that will terminate once quitflag is true. Funny how that works!

The problem is you don't seem to be trying. You don't even need five MINUTES of C++ education to use the trick I just used above.

i dont even kno what BOOLEn is, whenever it said that in the tutorial, i just skipped it, my bad, but i think i got it working

http://en.wikipedia.org/wiki/George_Boole

The creator of 'boolean algebra'.

Quote:

---

The problem is you don't seem to be trying. You don't even need five MINUTES of C++ education to use the trick I just used above.

---

In fact, you could get half way throught the whole language if you applied that 5 minutes to reading Learn C++ in 10 Minutes.