Calc challenge

I have almost the exact code from the challenge.

Code:

---

#include <iostream>

    int multiply(int x,int y)
    {
    return x*y;
    }
   
    int divide(int x, int y)
    {
    return x/y;
    }
   
    int add(int x, int y)
    {
    return x+y;
    }
   
    int subtract(int x, int y)
    {
    return x-y;
    }

using namespace std;

int main()
{
    char op='c';
    int x,y;
    while (op!=e)
    {
    cout<<"What operation would you like to perform add(+), subtract(-),divide(/),multiply(*), (e)exit?";
    cin>> op;
    switch(op)
    {
    case '+':
    cin>>x;
    cin>>y;
    cout<<x<<"+"<<y<<"="<<add(x,y)<<endl;
    break;
   
    case'-':
    cin>>x;
    cin>>y;
    cout<<x<<"-"<<y<<"="<<subtract(x,y)<<endl;
    break;
   
    case'/':
    cin>>x;
    cin>>y;
    cout<<x<<"/"<<y<<divide(x,y)<<endl;
    break;
   
    case'*':
    cin>>x;
    cin>>y;
    cout<<x<<"*"<<y<<multiply(x,y)<<endl;
    break;
    case'e':
    return 0;
    default:
    cout<<"sorry, try again."<<endl;
    }
    }
   
    return 0;
}

---

It says e is undeclared even though I filled in all the blanks on the challenge thing.

Hello,

Didn't you mean:

Code:

---

while (op!='e')

---

- Stack Overflow

hehehe oops...... thanks

I added another cout, because I didn't know if it was working after I entered + so now it prompts you to enter the number.
My finished product:

Code:

---

#include <iostream>

    int multiply(int x,int y)
    {
    return x*y;
    }
   
    int divide(int x, int y)
    {
    return x/y;
    }
   
    int add(int x, int y)
    {
    return x+y;
    }
   
    int subtract(int x, int y)
    {
    return x-y;
    }

using namespace std;

int main()
{
    char op='c';
    int x,y;
    while (op!='e')
    {
    cout<<"What operation would you like to perform add(+), subtract(-),divide(/),multiply(*), (e)exit?";
    cin>> op;
    switch(op)
    {
    case '+':
    cout<<"Enter the numbers you would like to add."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"+"<<y<<"="<<add(x,y)<<endl;
    break;
   
    case'-':
    cout<<"Enter the numbers you would like to subtract."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"-"<<y<<"="<<subtract(x,y)<<endl;
    break;
   
    case'/':
    cout<<"Enter the numbers you would like to divide."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"/"<<y<<divide(x,y)<<endl;
    break;
   
    case'*':
    cout<<"Enter the numbers you would like to multiply."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"*"<<y<<multiply(x,y)<<endl;
    break;
    case'e':
    return 0;
    default:
    cout<<"sorry, try again."<<endl;
    }
    }
   
    return 0;
}

---

Another victory for me! :D :p

Just finished the array challenge to.

Code:

---

#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    int array[8];
    for (int x=0; x<8; x++)
    cin>>array[x];
    for (int x=0; x<8; x++)
    cout<<array[x];
   
    cin.get();
    cin.ignore();
 
}

---

Now what should I do?

Code:

---

#include <iostream>

    int multiply(int x,int y)
    {
    return x*y;
    }
   
    int divide(int x, int y)
    {
    return x/y;
    }
   
    int add(int x, int y)
    {
    return x+y;
    }
   
    int subtract(int x, int y)
    {
    return x-y;
    }

using namespace std;

int main()
{
    char op='c';
    int x,y;
    while (op!='e')
    {
    cout<<"What operation would you like to perform add(+), subtract(-),divide(/),multiply(*), (e)exit?";
    cin>> op;
    switch(op)
    {
    case '+':
    cout<<"Enter the numbers you would like to add."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"+"<<y<<"="<<add(x,y)<<endl;
    break;
   
    case'-':
    cout<<"Enter the numbers you would like to subtract."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"-"<<y<<"="<<subtract(x,y)<<endl;
    break;
   
    case'/':
    cout<<"Enter the numbers you would like to divide."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"/"<<y<<"="<<divide(x,y)<<endl;
    break;
   
    case'*':
    cout<<"Enter the numbers you would like to multiply."<<endl;
    cin>>x;
    cin>>y;
    cout<<x<<"*"<<y<<"="<<multiply(x,y)<<endl;
    break;
    case'e':
    return 0;
    default:
    cout<<"sorry, try again."<<endl;
    }
    }
   
    return 0;
}

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Now when you multiply or divide it doesn't look like the second number is part of the answer. Otherwise excellent job.