Coin counting (logic problem)

Problem here. I assume that I put too many nested if and else statements and screwed up somewhere :x. Anyway, the project is:
Write a program to print the coins necessary to return change to a customer after a purchase. The change can be made up of quarters, dimes, nickels and pennies. You may assume that the amount of change is less than $1. Your program should use the minimum number of coins needed. Input the amount of change in cents.
Yeah, So I've been at this for a while and came up to the conclusion that I suck at programming. Help would be greatly appreciated :).
I get no value for Quarters (q) and everything else says its equal to 0 in the output.

Code:

---

#include <iostream.h>
#include <conio.h>

main()
{
    int q1, d1, n1, p1, ans, change;
    int q=0;
    int d=0;
    int n=0;
    int p=0;
   
 do
 {
    cout << "What is the change amount? ";
    cin >> change;
    if (change>25)
      do
      {
      q1=change-25;
      q++;
      change=change-(q*25);
      }
      while(q1>=25);
    else   
            if (change>10)
              do
              {
              d1=change-10;
              d++;
              change=change-(d*10);
              }
              while (d1>=10);
            else
                if (change>5)
                  do
                  {
                  n1=change-5;
                  n++;
                  change=change-(n*5);
                  }
                  while (n1>=5);
                else
                      if (change>1)
                        do
                        {
                        p1=change-1;
                        p++;
                        change=change-(p*1);
                        }
                        while (p1>=1);
                      else
                              cout << "Amount of quarters " << q << '\n';
                              cout << "Amount of dimes " << d << '\n';
                              cout << "Amount of nickels " << n << '\n';
                              cout << "Amount of pennies " << p << '\n';
                              cout << "\nTry again? (1 = yes, 2 = no): ";
                              cin >> ans;
  }
  while (ans=1);
  return 0;
}

---

Hey, I'm not that great at programming, but I could offer some help since two heads are better than one.

One tip is to load up your code with comments which is something your totally missing because its hard for people to follow what your doing since we are not in your head and on the same page of your thought process.

But from what I'm seeing and judging from your output, I think you have a problem with the if/else statements. The change variable enters the first if and I went through it using the number 37. It passes the first if statement test as it is greater than 25, so it performs the operations within the if statement. Therefore, q1 is updated to 12, q is icremented to 1, and change is updated to be 12 (which all makes sense).

However, since it passed the test for the if statement, wouldn't it skip the else statement because the if was satisfied. Therfore all of your nested if/else statements are ignored because the first if statement is performed and therefore it would not have to go to the else statement.

Hope this helps

Here is a program that calculates the amount of change in a given sum. I believe this might point you in the right direction for what you are doing.

Code:

---

#include <stdio.h>
#include <math.h>

void change(float, int*, int*, int*, int*); //function prototype

int main(void){

        float fMoney;
        int iQuarters, iDimes, iNickels, iPennies;

        //Prompt for money entry
        printf("Enter how much money you wish to convert to change: ");
        scanf("%f", &fMoney);

        //call our function to perform conversion
        change(fMoney, &iQuarters, &iDimes, &iNickels, &iPennies);

        //Display result
        printf("\nYou have %d quarters, %d dimes, %d nickels, and %d 
              pennies\n", iQuarters, iDimes, iNickels, iPennies);

        return(0);
}
//provide our function definition
void change(float fMoney, int* iQuart, int* iDime,
            int* iNick, int* iPenn) {

//Determine how many quarters, dimes, nickels and pennies are in the money provided
        *iQuart = (int)(fMoney / .25);
        fMoney = fMoney - (.25 * *iQuart);
        *iDime = (int)(fMoney / .10);
        fMoney = fMoney - (.10 * *iDime);
        *iNick = (int)(fMoney / .05);
        fMoney = fMoney - (.05 * *iNick);
        *iPenn = ceilf(fMoney*100); //ceilf used to counter rounding error experienced with floating point numbers
}

---

Happy Coding!!

Yeah, I had a feeling that those if/else statements would kill me. So i wrote it over a bit:

Code:

---

#include <iostream.h>
#include <conio.h>

main()
{
    int change;
    int ans;
    int q=0;
    int d=0;
    int n=0;
    int p=0;
   
    do
    {
    cout << "What is the change amount? ";
    cin >> change;

        do
        {
        q1=change-25;
        q++;
        change=change-(q*25);
        }
        while(change>=25);
                do
                {
                d1=change-10;
                d++;
                change=change-(d*10);
                }
                while (q1>=10);
                      do
                      {
                      n1=change-5;
                      n++;
                      change=change-(n*5);
                      }
                      while (d1>=5);
                            do
                            {
                            p1=change-1;
                            p++;
                            change=change-(p*1);
                            }                                                                   
                            while (n1>=1);
        cout << "Amount of quarters " << q << '\n';
        cout << "Amount of dimes " << d << '\n';
        cout << "Amount of nickels " << n << '\n';
        cout << "Amount of pennies " << p << '\n';
        cout << "\nTry again? (1 = yes, 2 = no): ";
        cin >> ans;
    }
    while (ans=1);
    return 0;
}

---

Now, My main problem here is that, it keeps going even after it has enough coins. Example: If the change was 90, it would give me 3 quarters, 1 dime, 1 nickel, and 1 penny which equals 91. I'm guessing there could be a simple solution to this.. Hopefully someone out there knows it. Thanks for the reply anyway swayp.

Hey, no problem I hoped I help.

I was looking at your updated code and it appears you updated half of it and forget the rest heh :).

You still have the variables q1,d1,etc. in there but they are not declared in the beginning, so which part did you mess up on. Did you not mean to use it or did you forget to declare it.

Judging from your output (although this could be totally off because I couldn't go through the code because of the above problem) one of your loops may be running one more time than you would like. Keep in mind that the do/while loop does the code automatically before it tests the condition. Then if the condition is still true, it will run again. If this is what you intended, just double check that it is running the right amount of times or perhaps implement it with a while loop.

If you want, you can post the updated code again and I'll look at it.

Alright let's go through this step by step soldier!
-----------------------
main returns an integer, so turn:

Code:

---

main()

---

into this:

Code:

---

int main()

---

-----------------------
Change this:

Code:

---

int q1, d1, n1, p1, ans, change;
int q=0;
int d=0;
int n=0;
int p=0;

---

to this (easier to read for ya)

Code:

---

int change;
int quarters=0, dimes=0, nickels=0, pennies=0;

---

-----------------------
You did good when asking for the change, but instead of doing it your way, make it into a loop, and STOP if there is no change left to deduct! First deduct change from the quarter, then the dime, etc. If you can deduct, go back to the top of the loop and continue deducting from the largest coin.
-----------------------
Now don't just copy this! Thou art must understand! Ask infinite questions if it needs be!

Code:

---

#include <iostream>
//#include <conio.h> Not standard C++ :(

// We could do: using namespace std;
// But we'd be including more than we need/want!
using std::cout;
using std::cin;
using std::endl;

int main() {
 int change;
 int quarters=0, dimes=0, nickels=0, pennies=0;


 cout << "What is the change amount? ";
 cin >> change;

 while(change > 0) {
  if(change >= 25) { // You found a quarter, now deduct it from the change
  quarters++;
  change -= 25;
  continue; // Go back to the top of the loop
  }

  if(change >= 10) { // You found a dime, now deduct it from the change
  dimes++;
  change -= 10;
  continue; // Go back to deduct from the highest coin
  }

  if(change >= 5) {
  nickels++;
  change -= 5;
  continue; // Go back to the top of the loop
  }

  if(change >= 1) {
  pennies++;
  change -= 1;
  continue;
  }
 }

 cout << "Quarters: " << quarters << endl;
 cout << "Dimes:    " << dimes  << endl;
 cout << "Nickels:  " << nickels  << endl;
 cout << "Pennies:  " << pennies  << endl;

 return 0;
}

---

Way too much computing power wasted on loops...As an example, this simple code will give you the total coins for quarters in one single pass.

Code:

---

if ( change >= 25 )
{
  quarters = change / 25;
  change %= 25;
}

---

Then it's a simple matter of passing the new value of change to the dimes.

Code:

---

if ( change >= 10 )
{
  dimes = change / 10;
  change %= 10;
}

---

etc...

Damn, you make it look so easy :)
Just one question, what's "change -= 25" I don't get what that's doing

And why should i use 'int main()' instead of main(), I was never taught 'int main()'.

I also have no clue why I was never taught "continue", as it's very useful.

1) change -= 25 is compiler shortcut for change = change - 25

2) Well for one reason Salem will kick your ass :p

Quote:

---

Originally Posted by andyhunter

2) Well for one reason Salem will kick your ass :p

---

He will kick your ass and then he'll kill your family!

I'll try and stay away from him..

But it's still not working..

I used some of what you told me,

Code:

---

#include <iostream.h>
#include <conio.h>

main()
{
    int change;
    int q=0,d=0,n=0,p=0;
   
    while(change > 0)
    {
    if (change >= 25)
    {
    q++;
    change = change - 25
    continue;
    }
    if(change >= 10)
    {
    d++;
    change = change - 10;
    continue;
    }
    if(change >= 5)
    {
    n++;
    change = change - 5;
    continue;
    }
    if(change >=1)
    {
    p++;
    change = change - 1;
    continue;
    }
  }   
        cout << "Amount of quarters " << q << '\n';
        cout << "Amount of dimes " << d << '\n';
        cout << "Amount of nickels " << n << '\n';
        cout << "Amount of pennies " << p << '\n';
    return 0;
}

---

I also tried compiling yours, and when I enter something in, it crashes. Maybe it's because im using the dev c++ compiler? D:

compile who's?

Quote:

---

Originally Posted by xlokix

I also have no clue why I was never taught "continue", as it's very useful

---

It makes you go back to the top of the loop. break gets you out of the current loop. This is an infinite loop:

Code:

---

do {
    continue;
} while(false); // Break out of the loop once you get here

---

This is your crash fix:

Code:

---

while(change > 0)
    {
    if (change >= 25)
    {
    q++;
    change = change - 25
    continue;
    }
    if(change >= 10)
    {
    d++;
    change = change - 10;
    continue;
    }
    if(change >= 5)
    {
    n++;
    change = change - 5;
    continue;
    }
    if(change >=1)
    {
    p++;
    change = change - 1;
    continue;
    }
} // <-- You forgot to stop your while loop

---

Keep asking questions, anything that you don't understand quite.

The continue statement is only used in while, for, and do/while loops.

Try the method I posted a few mins ago.

[edit]..ne'r mind. I just noticed you had the if statements enclosed in a while. Still I'd recommend the 1 pass method.

hold on, checking it over.

Whoa whoa!
You forgot to ask the user how much change he/she has!

Code:

---

cout << "What is the change amount? ";
cin >> change;

---

Ok, look at this

Code:

---

#include <iostream>
//#include <conio.h> Not standard C++ :(

// We could do: using namespace std;
// But we'd be including more than we need/want!
using std::cout;
using std::cin;
using std::endl;

int main() {
 int change;
 int quarters=0, dimes=0, nickels=0, pennies=0;


 cout << "What is the change amount? ";
 cin >> change;

while(change > 0)
    {
    if (change >= 25)
    {
    quarters++;
    change = change - 25;
    continue;
    }
    if(change >= 10)
    {
    dimes++;
    change = change - 10;
    continue;
    }
    if(change >= 5)
    {
    nickels++;
    change = change - 5;
    continue;
    }
    if(change >=1)
    {
    pennies++;
    change = change - 1;
    continue;
    }
} // <-- You forgot to stop your while loop

 cout << "Quarters: " << quarters << endl;
 cout << "Dimes:    " << dimes  << endl;
 cout << "Nickels:  " << nickels  << endl;
 cout << "Pennies:  " << pennies  << endl;

 return 0;
}

---

This crashes BUT I can see just as it crashes, that the logic is correct. (I entered 35, and got 1 quarter, and 1 dime) then it crashed.

Probably not crashing. Probably just closing. Check the FAQ for information on how to stop this from happening.

hey pal listen to scribbler. you are going to complex for an easy task. Look at the program that I posted on the first page. On 1 pass it calculates the change.

Code:

---

void change(float fMoney, int* iQuart, int* iDime,
            int* iNick, int* iPenn) {

//Determine how many quarters, dimes, nickels and pennies are in the money provided
        *iQuart = (int)(fMoney / .25);
        fMoney = fMoney - (.25 * *iQuart);
        *iDime = (int)(fMoney / .10);
        fMoney = fMoney - (.10 * *iDime);
        *iNick = (int)(fMoney / .05);
        fMoney = fMoney - (.05 * *iNick);
        *iPenn = ceilf(fMoney*100); //ceilf used to counter rounding error experienced with floating point numbers
}

---

fMoney would be the change. If you have questions on this implementation just ask.

Quote:

---

Originally Posted by xlokix

This crashes BUT I can see just as it crashes, that the logic is correct. (I entered 35, and got 1 quarter, and 1 dime) then it crashed.

---

Code:

---

#include <stdio.h>
------------------[BLAHBLAHBLAH]
cout << "Quarters: " << quarters << endl;
cout << "Dimes:    " << dimes  << endl;
cout << "Nickels:  " << nickels  << endl;
cout << "Pennies:  " << pennies  << endl;

getchar();getchar();

return 0;
}

---

Try adding the snippets that to the source so that the window doesn't autoclose!

Well I'm trying to keep it simple, My teacher probably wouldn't believe I wrote the code if I included stdio.h, since we've never learned that before. Or getchar (whatever the hell that is :confused: ). But yes, that did fix the crash. Is there another way around it without stdio.h ?

Here, I'll update on what I have so far.

Code:

---

#include <iostream.h>
#include <stdio.h>


main()
{
    int change;
    int q=0,d=0,n=0,p=0;
    cout << "What is the change?";
    cin >> change;
   
    while(change > 0)
    {
    if (change >= 25)
    {
    q++;
    change = change - 25;
    continue;
    }
    if(change >= 10)
    {
    d++;
    change = change - 10;
    continue;
    }
    if(change >= 5)
    {
    n++;
    change = change - 5;
    continue;
    }
    if(change >=1)
    {
    p++;
    change = change - 1;
    continue;
    }
  }   
        cout << "Amount of quarters " << q << '\n';
        cout << "Amount of dimes " << d << '\n';
        cout << "Amount of nickels " << n << '\n';
        cout << "Amount of pennies " << p << '\n';
    getchar();getchar();
    return 0;
}

---

This is what getchar() does: It basically just asks for user input.

Code:

---

#include <iostream> // Allow us to use cout and endl
#include <stdio.h> // Allows us to use getchar();

// We could also do:
// using namespace std;
using std::endl;
using std::cout;

int main() { // Main always returns an integer!
    // Gets a character from console input (like cout), except only ONE character!
    // Not a string
    int myCharacter = getchar();
    cout << myCharacter << endl;
    return 0;
}

---

If your teacher looks at the source and goes: "WTH", then you can explain it to him, as far as what everything does! And if he still doesn't believe you, then send him to this forum topic, and he'll probably be like:
"Wow somebody asked for help! Holy ****! 50 points extra credit for you!" lol :)

---EDIT---
Be sure to test this out, practice makes perfect!

I don't recommend telling a C++ student to use C functions, and then challenge the instructor. There's a curriculum to follow and all you'll do is throw a rock into the machine. Not to mention that is a complete garbage solution to what he's asking. There is a member function of cin which would suit perfectly, however I'd sooner let his curriculum teach the method first. Just giving the answers robs him of a valuable learning tool...studying.

In my experience, instructors don't look at the compiled/executable file. They are only interested in the sourcecode which they look over themselves to verify the student has grasped the concepts the project places before them (as well as observe their logic skills). The window closing upon program exit is a non issue.

Alright, heres a C++ approach still using the one pass way yet no floats or strange rounding functions:

Code:

---

#include <iostream>
#include <math.h>

using namespace std;

int main() {

        int fChange;
        int Quart, Dime, Nick, Penn;

        cout << "Enter the change:";
        cin >> fChange;
        //calculate change on 1 pass
        Quart = (fChange / 25);
        fChange = fChange - (25 * Quart);
        Dime = (fChange / 10);
        fChange = fChange - (10 * Dime);
        Nick = (fChange /5);
        fChange = fChange - (5 * Nick);
        Penn = fChange;

        cout << "Quarters: "<< Quart << endl;
        cout << "Dimes: " <<Dime << endl;
        cout << "Nickels: "<< Nick << endl;
        cout << "Pennies: " << Penn << endl;

        return 0;
}

---

Actually, I'm in C++ 1, and there will be no C++ 2 next year. So I will not learn more. And it's only a half a year class, so I'm finished with the class in about a week.

Quote:

---

Originally Posted by andyhunter

Alright, heres a C++ approach still using the one pass way yet no floats or strange rounding functions:

---

Mine was very similar. And since so many people have already posted code, I might as well follow suit.

Code:

---

#include <iostream>
using std::cout;
using std::cin;
using std::endl;

main()
{
        int quarters, dimes, nickels, pennies;
        int change;

        cout << "What is the change amount? ";
        cin >> change;
       
        quarters = change / 25;
        change %= 25;
        dimes = change / 10;
        change %= 10;
        nickels = change / 5;
        change %= 5;
        pennies = change;
       
        cout << "Amount of quarters " << quarters << endl;
        cout << "Amount of dimes " << dimes << endl;
        cout << "Amount of nickels " << nickels << endl;
        cout << "Amount of pennies " << pennies << endl;

        return 0;
}

---

Before the way I'm using now, I wrote something similar to scribblers way and got weird numbers so I changed my method.

Ok. Next up, Project 2!
Oh boy this is going to be a long one. The user thinks of a number, and the program guesses. The program makes a guess of 50, then the user tells whether it's higher or lower until the program eventually gets it.
Booo! I'm gonna eat dinner before I start this. Leave some suggestions on how to start it if you want. I presume that there will be a hell of a lot of nested if statements.

I won't post any code for that project, but it's a typical learning tool.

Hint. Search your textbook for binary search method.

Quote:

---

Quote:
Originally Posted by andyhunter
Alright, heres a C++ approach still using the one pass way yet no floats or strange rounding functions:

Mine was very similar. And since so many people have already posted code, I might as well follow suit.

---

Of course, there are only so many ways of solving a particular problem. And I do recall saying :

Quote:

---

hey pal listen to scribbler

---

One solution was originally in C and one in C++. No reason to get all huffy.

edit: Not to mention I wasn't attempting to give him a solution for his first post. Just show him a similar solution where the algorithm was important, not the implementation. That's why my first post said this:

Quote:

---

Here is a program that calculates the amount of change in a given sum. I believe this might point you in the right direction for what you are doing.

---

--EDIT--
Sorry about that andyhunter ;)

Kleid-0 - sshhh

Quote:

---

won't post any code for that project, but it's a typical learning tool.

Hint. Search your textbook for binary search method.

---

See, we agree on stuff.

Quote:

---

Originally Posted by andyhunter

One solution was originally in C and one in C++. No reason to get all huffy.

---

Sorry, I think you misunderstood and thought that comment was directed toward you. It wasn't. The distinction I made about C and C++ was directed to when the OP was receiving advice to mix C code within his C++ code (ie. inlcuding stdio.h and using the getchar function), and then advised to defend poor design to the instructor to boot.

I then posted my code to show that you and I were on the same page :cool:

Couldn't find the Binary Search Method in my textbook...
Anyway, I started it...

Code:

---

#include <iostream.h>
main()
      int guess, ans, ans2;
      int high = 100;
      int low = 1;
     
      cout << "Think of a number between 1 and 100\n";
      cout << "My first guess is 50, is your number higher, lower, or 50?";
      cout << "\n(higher = 1, lower = 2, correct guess = 0)";
      cin >> ans;
     
      if (ans = 1)
        low = 50;
        cout << "My guess is 75, is your number higher, lower, or 75?";
        cout << "\n(higher = 1, lower = 2, correct guess = 0)";
              if (ans2 = 1)
                high = 100;
                low = 76;
                cout << "My guess is 88, is your number higher, lower, or 88?";
                cout << "\n(higher = 1, lower = 2, correct guess = 0)";
              else
                  if (ans2 = 2)
                  high = 74;
                  low = 51;
                  cout << "My guess is 62, is your number higher, lower, or 62?";
                  cout << "\n(higher = 1, lower = 2, correct guess = 0)";
                  if (ans2 = 0)
                  ???????????
                  ???????????

---

What would I put where the question marks are, to end the program?
I'm probably starting this wrong anyway. So maybe a few suggestions would help. I started with, if the user entered 1, as in the number is greater than 50.

Quote:

---

Actually, I'm in C++ 1, and there will be no C++ 2 next year. So I will not learn more. And it's only a half a year class, so I'm finished with the class in about a week.

---

Dude, have you been sleeping throught this class?

edit:

Ok here is some psuedocode:

Code:

---

Set guessnumber = 0
Set a "found" flag to false
Set lower index to min number (your case 0)
Set higher number to max number(your case 100)
while found is false
      guess = (max + min) / 2
      Ask if lower or higher
      if higher then
              min = guess
      if lower than
              max = guess
      if guess = number then
              found = true
      guessnumber = guessnumber + 1
loop
Print I guessed your number in guessnumber tries

---

This should help.

No, there's no room to sleep on the desk with the computer there and all.

Look above I edited my post.

Ahhhhh. Let me try this out.

What do you mean by "found", never done that before :x

Just an integer variable indicating a true (1) or false (0) condition to be used in the while loop.

Code:

---

bool found = false;

---

And remember pseudo doesn't exactly have to deal with the language's symantics.

Blah!!! I was sure I got it this time. Anyway, I need help again.
I'm not sure if it's just crashing, or it's closing again. But I tried the getchar();getchar(); and that didn't stop it from closing, so I don't know.

Code:

---

#include <iostream.h>

main()
{
    int max = 100;
    int min = 1;
    int guess, ans;
   
    cout << "Think of a number between 1 and 100 and I will try to guess it\n";
  do
  {
    guess = (max+min) / 2;
    cout << "My guess is " << guess << ", is your number higher,lower, or 50?\n";
    cout << "(higher = 1, lower = 0, correct guess = 2)";
   
    if (ans = 1)
        min = guess;
    if (ans = 0)
        max = guess;
    if (ans = 2);
  }
  while (ans != 2)
  cout << "I guessed your number!";
  return 0;
}

---

For those who don't know, The objective of the program was for the user to think of a number between 1 and 100 and the program tries to guess what number it is.

edit:

Code:

---

#include <iostream.h>
#include <stdio.h>

main()
{
    int max = 100;
    int min = 1;
    int guess, ans;
   
    cout << "Think of a number between 1 and 100 and I will try to guess it\n";
  do
  {
    guess = (max+min) / 2;
    cout << "My guess is " << guess << " is your number higher,lower, or 50?\n";
    cout << "(higher = 1, lower = 0, correct guess = 2)";
    cin >> ans;
   
    if (ans = 1)
        min = guess;
        else
            if (ans = 0)
            max = guess;
                else
                    if (ans = 2)
  }
  while (ans != 2); 
  cout << "I guessed your number!";
  getchar();getchar();
  return 0;
}

---

Well, I corrected myself, It works good now.
P.S. thanks for the pseudo code!

edit edit: Actually It's still messed up, 0 and 2 don't work, no matter what I press it keeps going as if I went higher.

I see this in your code

Code:

---

    if (ans = 1)

---

It will never make it past the first "if" because you are assigning "=" 1 to ans so it will always be true. I think you want to compare "==" to 1 so that would be this.

Code:

---

    if (ans == 1)

---

I only picked the first one you have two more to look at.

Code:

---

        else
            if (ans = 0)
            max = guess;
                else
                    if (ans = 2)

---

Ahhhhhhhhh! My teacher would kill me for that. Woops! Thanks man, that worked :p.

Here's one solution I wrote a while ago:
The comments, variable names and money is in Swedish, so try to figure the code out as an excercise. :)

Code:

---

int main()
{
    using namespace std;
   
    //De här fälten innehåller de sedlar och namn på sedlar vi använder
    //Endast dessa behöver ändras vid en enventuell införsel av Euro
    const int  valorer[]  = {500,100,50,20,10,5,1,0};
    const char* valorNamn[] = {"Femhundralappar","Hundralappar","Femtiolappar","Tjugolappar","Tiokronor",
                              "Femkronor","Enkronor",0};

    //Hämta input
    int belopp, betalat;
    cout << "Skriv in belopp: ";
    cin >> belopp;
    cout << "Skriv in hur mycket du betalar med: ";
    cin >> betalat;

    //Beräkna växel
    int tillbaka = betalat - belopp;

    cout << "Tillbaka " << tillbaka << " kronor" << endl;

    //Gå igenom listan med de olika valörerna
    const int*  valor = valorer;
    const char** namn  = valorNamn;
    while (*valor && *namn)
    {
        //Så här många av denna typ ges tillbaka
        const int antal = tillbaka / *valor;
        //Minska summan med summan vi nu ger tillbaka
        tillbaka = tillbaka % *valor;

        //Visa att vi ger tillbaka
        cout << *namn << " : " << antal << endl;
       
        ++valor;
        ++namn;
    }
}

---

It's like you're speaking 3 different languages!

Ok I have one little problem and that's all I'm asking out of these forums (for now at least)!

I have a project that I have to do, you have to display this with loops:

*
**
***
****
*****

Now you can't just write

Code:

---

cout << "*\n";
cout << "**\n";

---

etc.
I'm supposed to write it with loops. This is all I have so far, and all I can get is a row of *'s going vertical :\ Sorry for asking so many questions, but it's probably a simple project, I've just never done anything like this before.

Code:

---

#include <iostream.h>
#include <stdio.h>

main()
{
      int asterisks = 0;
      do
      {
      cout << "*\n";
      asterisks++;
      }
      while (asterisks < 6);
      getchar();getchar();
      return 0;
}

---

Why don't you look into using for()?

Code:

---

for (int x = 0; x < MAX_STARS; x++)
{
    // Your code for handling the loop here
}

---

Edit: I'll be nice and give another hint.

Your life will be a lot easier if you insert a while() loop into your for() loop. Allow me yet another example.

Code:

---

#define MAX_STARS 6

// int main() stuff..

int y = 0;

for (int x = 0; x < MAX_STARS; x++)
{
    while (y <= x)
    {
        // Handle your std::cout and y increment here
    }
}

---

Edit 2: I just played around with code for a second and made up a function to do something like this:

Quote:

---

*
**
***
****
*****
******
*****
****
***
**
*

---

Only go to the following link if you are truly and completely stumped on the problem: http://lithorien.net:5001/test.cpp

Actually, for the test that was today, there were 3 programs I had to know, and one of them would be on the test. Thankfully, one of the three programs on it was the one I knew (the asterisks one being the 3rd the one i didnt know). So I don't need it anymore, thanks for the help anyway D:
Looks simpler than I thought.