Return 2 variables?

Is it possible to return 2 variables for ex.

Code:

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int hello(int x, int y)
{
  x++;
  y++;
  return x,y;
}

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Example:

Code:

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void hello(int &x, int &y) {
  x++;
  y++;
}

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No. But you can wrap them up in a struct and then return the struct.

Code:

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struct Return2Ints {
  int x;
  int y;
};

Return2Ints hello (int x, int y)
{
  return Return2Ints(x+1,y+1);
}

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how would i recieve it?

Code:

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x = return2numbers();

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xbeing a struct?

From Thantos' example:

Code:

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Return2Ints someStruct = hello (1,2);

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Adding to bithub:
To get to the actual values

Code:

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int a = someStruct.x;
int b = someStruct.y;

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A generic way to do this is to return an std::pair:

std::pair<int,int> hello(int x, int y); { return std::make_pair (x,y); }

std::pair bla = hello(1,2);
cout << bla.first; //x

Tuples (look up Boost.Tuple) let you return any number of values. You can use Boost.Tuple in a similar way to std::pair.

>> return Return2Ints(x+1,y+1);
Return2Ints needs a proper constructor for that to work.

Code:

---

struct Return2Ints {
  int x;
  int y;

  Return2Ints(int x_, int y_) : x(x_), y(y_) {}
};

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gg

Opps forgot about that. Though it can be done without a constructor:

Code:

---

Return2Ints hello(int x, int y)
{
  Return2Ints ret = {x+1,y+1};
  return ret;
}

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Quote:

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Originally Posted by azteched

A generic way to do this is to return an std::pair:

std::pair<int,int> hello(int x, int y); { return std::make_pair (x,y); }

std::pair<int,int> bla = hello(1,2);
cout << bla.first; //x

Tuples (look up Boost.Tuple) let you return any number of values. You can use Boost.Tuple in a similar way to std::pair.

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Added part in red above.