Sending array's to functions by reference or pointers

**homeyg** · 12-27-2004

Hmmm, I was trying to use the i's to try and fix the copying over problem and I guess I never got a chance to clean up the code a little. Here, how's this:

Code:

#include <iostream>
#include <cstring>

using namespace std;

void stringReverser(char* array, int len);

int main()
{
    char array[50];
    
    cout<<"Please enter a string to have it reversed: ";
    cin.get(array,49);
    int length = strlen(array);
    stringReverser(array,length);
    cout<<"Your string reversed is: "<<array<<endl;
    
    system("PAUSE");
    return 0;
}

void stringReverser(char* array, int len)
{
    char newArray[50];
    
    int j = len-1;
    for(int i = 0;i<len;i++,j--)
    {
        newArray[i]=array[j];
    }
    for(int i = 0;i<len;i++)
    {
        array[i]=newArray[i];
    }            
}

**elad** · 12-27-2004

here's an alternate version based on Salems suggestion:

Code:

void stringReverser(char* array, int len)
{
   char ch;
   for(int i = 0; i < len/2; ++i)
   {
	  //swap chars in same space without temporary holding array.
	  ch = array[x];
	  array[x] = array[len - 1 - x];
	  array[len - 1 - x] = ch;
   }
};

If you are allowed to use standard functions, you could consider using std::swap() from the std::algorithm header instead of the three line swap code in the for loop.

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