Sending array's to functions by reference or pointers

This is a discussion on Sending array's to functions by reference or pointers within the C++ Programming forums, part of the General Programming Boards category; Hmmm, I was trying to use the i's to try and fix the copying over problem and I guess I ...

  1. #16
    C/C++ homeyg's Avatar
    Join Date
    Nov 2004
    Location
    Louisiana, USA
    Posts
    209
    Hmmm, I was trying to use the i's to try and fix the copying over problem and I guess I never got a chance to clean up the code a little. Here, how's this:

    Code:
    #include <iostream>
    #include <cstring>
    
    using namespace std;
    
    void stringReverser(char* array, int len);
    
    int main()
    {
        char array[50];
        
        cout<<"Please enter a string to have it reversed: ";
        cin.get(array,49);
        int length = strlen(array);
        stringReverser(array,length);
        cout<<"Your string reversed is: "<<array<<endl;
        
        system("PAUSE");
        return 0;
    }
    
    void stringReverser(char* array, int len)
    {
        char newArray[50];
        
        int j = len-1;
        for(int i = 0;i<len;i++,j--)
        {
            newArray[i]=array[j];
        }
        for(int i = 0;i<len;i++)
        {
            array[i]=newArray[i];
        }            
    }
    Last edited by homeyg; 12-27-2004 at 02:28 PM.

  2. #17
    Registered User
    Join Date
    Mar 2002
    Posts
    1,595
    here's an alternate version based on Salems suggestion:
    Code:
    void stringReverser(char* array, int len)
    {
       char ch;
       for(int i = 0; i < len/2; ++i)
       {
    	  //swap chars in same space without temporary holding array.
    	  ch = array[x];
    	  array[x] = array[len - 1 - x];
    	  array[len - 1 - x] = ch;
       }
    };
    If you are allowed to use standard functions, you could consider using std::swap() from the std::algorithm header instead of the three line swap code in the for loop.

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