Thread: calling functions from functions

I know how to call a function from main, but it doesn't work from functions. Heres an example code.

Code:

#include <iostream.h>

void functiona()
{
  cout<<"Hello there";
  functionb();           //this doesn't work!!!
}

void functionb()
{
cout<<"Another hello";
cin.get();
}

int main()
{
  functiona();           //this works
}

The compiler says that the is no comparison with int functionb()

So how do I tell it that its void functionb()

Thanks in advance.

You just need to prototype it. Try this

Code:

void functiona();
void functionb();

int main()
{
  functiona();
}

void function a()
{
  cout<<"Hello there";
  functionb();
}

void functionb()
{
  cout<<"Another Hello";
  cin.get();
}

Prototyping just lets the compiler know that there is a function defined somewhere that has a certain name, return type, and parameters. Once it knows it exists somewhere it can make the call and then it lets the linker resolve it.

Just do some small changes:

Code:

Code:
#include <iostream>   // Drop the .h to comply to the standard
using namespace std;    // Tell the compiler that we want to use what is in the standard namespace.

// These are called function prototypes and basicly tells the compiler that the functions exists
void functiona();    
void functionb();

int main()
{
  functiona();           //this works
}

// Here comes the function definition/decleration (dont know what they are called lol) and just tells what the function does. 

void functiona()
{
  cout<<"Hello there";
  functionb();           //this doesn't work!!!
}

void functionb()
{
 cout<<"Another hello";
 cin.get();
}

Edit: damn! beaten!

thanks... I tried it on my programme and it works