Thread: modigy array elements..?

sorry this is correct:

Code:

#include <iostream>
#include <stdlib.h>

using namespace std;

void messageFunction();
void Header();

int main()
{


int a=0;

int num;

Titlos();
cout<<endl;
messageFunction();

cout<<"Choose an option:"<<endl;
cin>>num;

while (num==1&&a<5)
{
      a++;

      cout<<"You bought seat "<<a<<endl;
      cin>>a;
      break;
           
}

return main();

  system("PAUSE");	
  return 0;
}

void messageFunction(void)
{
    cout<<"Type 1 for First class"<<endl;
} 

void Header()

{
    cout<<"********Exercise 3 Solution********"<<endl;
}

could someone solve my prob?

>return main();
Recursive calls to main aren't legal C++. Use a loop instead.

ok, i have tryied a lot of patterns but with no result..

>i have tryied a lot of patterns but with no result..
It would help if you explained exactly what input you want to give, and what output you expect. There are many times when just looking at the code doesn't help us to understand your intentions at all. Is this what you want?

Code:

#include <iostream>
#include <cstdlib>

using namespace std;

void messageFunction();
void Header();

int main()
{
  int a=0;
  int num;

  Header();

  do
  {
    cout<<endl;
    messageFunction();

    cout<<"Choose an option:"<<endl;
    cin>>num;

    if (num == 1)
    {
      a++;
      cout<<"You bought seat "<< a <<endl;
    }
    else
    {
      break;
    }
  } while (a < 5);

  system("PAUSE");

  return 0;
}

void messageFunction(void)
{
  cout<<"Type 1 for First class"<<endl;
} 

void Header()
{
  cout<<"********Exercise 3 Solution********"<<endl;
}

If not, you'll need to describe what you want, in painful detail.

Yes..thanks!

Originally Posted by Prelude

>I meant as 1 (which would be array[0]).
Your code was misworded too then:

Code:

int array[0]; // Illegal
int array[1]; // Legal, but kind of silly because only array[0] is available

No my code worked as intended in my compiler o-o

Code:

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    int in;
    int array[0];
    array[0]=0;
    cout<<"Please enter a number";
    cin>>in;
    array[0]=in;
    cout<<"Array value is now:"<<array[0];
    system("PAUSE");
    return 0;
}

>No my code worked as intended in my compiler o-o
My compiler can beat up your compiler.

Originally Posted by Prelude

My compiler can beat up your compiler.

Dev-CPP + $120 > Visual C++


edit: not really, but I do like my money in my pocket for now

>Dev-CPP + $120 > Visual C++
Who said I was talking about Visual C++? I was making a "My dad can beat up your dad" joke, but that doesn't change the fact that your excuse for broken code was that it happened to work on your implementation. That's a horrible excuse, but I'll let it slide because Dev-C++ really does compile it without warnings. Though I'll continue to wonder how you thought an array of size 0 should work.