never seen a type *fnc (params); before, need clarification on use

I've never seen something like:

Code:

class IdClass {
  public:
    IdClass();			// initialize the list
    ~IdClass();			// de-allocate the list

    void Add (void *item, int Key);	// Put item into list
    void *Remove (int Key);
  private:
    IdElement *first;  	// Head of the list, NULL if list is empty
    IdElement *last;		// Last element of list
};

void * IdClass::Remove (int a)
{
  IdElement * tmp = first, * prev = (IdElement *)NULL;
  while ((tmp != NULL) && (tmp->key != a))
  {
    prev = tmp;
    tmp = tmp->next;
  }
  //more code in function here
  return value;
}

How do I use the Remove function if I'm instantiating an instance like this:

Code:

IdClass *test;
test = new IdClass();

//for add I can do this
test->Add(itemptr,5);

I don't know how to call Remove. I've never seen that syntax before. And what does that syntax mean?

void *Remove (int Key);
a function that takes an int and returns a void pointer. in c++ you need to cast the return value to the needed type, i think, not sure

Code:

int main()
{
  ....
  test.Remove(5);
  ....
}

>>I've never seen that syntax before. And what does that syntax mean?

what part of the which syntax don't you understand?

thanks for the info. and from that info, if "test" was not a pointer to the instance but rather the instance itself, the call to Remove would be

Code:

test->Remove(5);

right?

I didn't realize the function was returning a pointer of the type, so I didn't know what was the purpose of defining the function that way. Now I know. thanks.

My bad.

test.Remove(5); if test is an object and
test->Remove(5); if test is a pointer to an object.

Sorry. Didn't register in my noggin that test was declared dynamicaly