1. help with magic square

Hi, I like to learn how to make a magic square.

I know how to do a single like of array, but when it comes to making 5 dimension magic square i have know idea how to do . If someone can type the code on here so that i can study it and learn it, that will be grateful

have a Happy Thanksgivings

2. 5 dimensions?? I've already played with a 4D one.
Or you're saying the small square with NxN dimensions whose sum of lined numbers is constant?
If you have a N*N square, it'll have numbers from 1 to N*N. The sum of all numbers will be (N*N+1)*N/2, therefore one line will result in sum (N*N+1)*N/2/N.
Example: in a 5*5 square all numbers sum up to 325, therefore a line will have sum 325/5 = 65. Then you'll have a linear system of equations. Have fun solving them

4. Code:
```#include <iostream>
#include <vector>

using namespace std;

void OddMagicSquare(vector<vector<int> > &matrix, int n);
void DoublyEvenMagicSquare(vector<vector<int> > &matrix, int n);
void SinglyEvenMagicSquare(vector<vector<int> > &matrix, int n);
void MagicSquare(vector<vector<int> > &matrix, int n);
void PrintMagicSquare(vector<vector<int> > &matrix, int n);

int main(int argc, char* argv[])
{
int n;
printf("Enter order of square: ");
scanf("%d", &n);

vector<vector<int> > matrix(n, vector<int> (n, 0));

if (n<3)
{
printf("\nError: n must be greater than 2\n\n");
return -1;
}

MagicSquare(matrix, n);

//Print results
PrintMagicSquare(matrix, n);

return 0;
}

void MagicSquare(vector<vector<int> > &matrix,int n)
{
if (n%2==1)        //n is Odd
OddMagicSquare(matrix, n);
else          //n is even
if (n%4==0)    //doubly even order
DoublyEvenMagicSquare(matrix, n);
else      //singly even order
SinglyEvenMagicSquare(matrix, n);
}

void OddMagicSquare(vector<vector<int> > &matrix, int n)
{
int nsqr = n * n;
int i=0, j=n/2;     // start position

for (int k=1; k<=nsqr; ++k)
{
matrix[i][j] = k;

i--;
j++;

if (k%n == 0)
{
i += 2;
--j;
}
else
{
if (j==n)
j -= n;
else if (i<0)
i += n;
}
}
}

void DoublyEvenMagicSquare(vector<vector<int> > &matrix, int n)
{
vector<vector<int> > I(n, vector<int> (n, 0));
vector<vector<int> > J(n, vector<int> (n, 0));

int i, j;

//prepare I, J
int index=1;
for (i=0; i<n; i++)
for (j=0; j<n; j++)
{
I[i][j]=((i+1)%4)/2;
J[j][i]=((i+1)%4)/2;
matrix[i][j]=index;
index++;
}

for (i=0; i<n; i++)
for (j=0; j<n; j++)
{
if (I[i][j]==J[i][j])
matrix[i][j]=n*n+1-matrix[i][j];
}
}

void SinglyEvenMagicSquare(vector<vector<int> > &matrix, int n)
{
int p=n/2;

vector<vector<int> > M(p, vector<int> (p, 0));
MagicSquare(M, p);

int i, j, k;

for (i=0; i<p; i++)
for (j=0; j<p; j++)
{
matrix[i][j]=M[i][j];
matrix[i+p][j]=M[i][j]+3*p*p;
matrix[i][j+p]=M[i][j]+2*p*p;
matrix[i+p][j+p]=M[i][j]+p*p;
}

if (n==2)
return;

vector<int> I(p, 0);
vector<int> J;

for (i=0; i<p; i++)
I[i]=i+1;

k=(n-2)/4;

for (i=1; i<=k; i++)
J.push_back(i);

for (i=n-k+2; i<=n; i++)
J.push_back(i);

int temp;
for (i=1; i<=p; i++)
for (j=1; j<=J.size(); j++)
{
temp=matrix[i-1][J[j-1]-1];
matrix[i-1][J[j-1]-1]=matrix[i+p-1][J[j-1]-1];
matrix[i+p-1][J[j-1]-1]=temp;
}

//j=1, i
//i=k+1, k+1+p
i=k;
j=0;
temp=matrix[i][j]; matrix[i][j]=matrix[i+p][j]; matrix[i+p][j]=temp;

j=i;
temp=matrix[i+p][j]; matrix[i+p][j]=matrix[i][j]; matrix[i][j]=temp;
}

void PrintMagicSquare(vector<vector<int> > &matrix, int n)
{
for (int i=0; i<n; i++)
{
for (int j=0; j<n; j++)
printf(" %3d", matrix[i][j]);

printf("\n");
}

printf("\n\n");
}```