How to multiply and Divide Huge int numbers

This is a discussion on How to multiply and Divide Huge int numbers within the C++ Programming forums, part of the General Programming Boards category; I need some help on a program for school that I am supposed to be able to input a integer ...

  1. #1
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    How to multiply and Divide Huge int numbers

    I need some help on a program for school that I am supposed to be able to input a integer number of unlimited size and mulitply it with another as well as divide,subtract, and add them. I have the add and subtract working. I read them as a string then convert each digit to a interger stored in a vector array and work it a digit at a time for the add and subtract. It works although its a bit awkward. I have no clue on the multiply and divide. Help before I loose all my hair.

    thanks

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    i remember i made that exercise a long time a go i cant help you a lot but will try to give you the basics of the multiply and division how i did it.

    as you said you have no problems with the add, the rest of operations reduce to the add operations ie:

    to multiply 2 numbers:
    4*8 = 32
    the result is the sum of the first number until you get the second number
    or the sum of 8 times 4
    4+4+4+4+4+4+4+4 = 32

    to divide 2 numbers:
    is the inverse of the multiply
    8/2 = 4

    2+2+2+2 = 8 as you see you have "4" "2's" and 4 is the answer

    ok, as i told you i made that exercise a long time a go and cant remember how i did it or where's the source code, but thats the "key" i found to solve that problem .
    will try to find it, should be somewere

    please excuse my poor english and good luck

  3. #3
    Registered User jlou's Avatar
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    You can also use basic elementary school multiplication and division methods that go one digit at a time.

  4. #4
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    you can implement the multiply and divide using addition and substraction which you had implemented like this:
    code:
    Code:
    class longInteger {
    public:
    .........
        longInteger operator+(const longInteger& oprand);    
        longInteger operator+(int opint);    
        longInteger operator-(longInteger& oprand);
        longInteger operator*(longInteger& oprand);
        longInteger operator/(longInteger& oprand);
    ........
    private:
    ......
    
    };
    
    longInteger longInteger::operator*(longInteger& oprand) {
    longInteger result(*this),i;
        for(i=0;i<oprand;i=i+1)
            result = result + *this
        }
        return result
    }
    
    
    longInteger longInteger::operator/(longInteger& oprand) {
    longInteger result(0), val(*this);
    
             while((val = (val - oprand)) >0) {
                    result = result +1;
              }
        return result
    }

    also you have to implement the operator>, constructor,copy constructor, operator=, ...
    I just give you a algorithm, my code might not work cuz I haven't had it tested.
    Hope it could help you!

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