I'm back! need help with a simple copy program

This is a discussion on I'm back! need help with a simple copy program within the C++ Programming forums, part of the General Programming Boards category; I made a really simple program that copys 4 files (defined in teh source code) and copys them to the ...

  1. #1
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    I'm back! need help with a simple copy program

    I made a really simple program that copys 4 files (defined in teh source code) and copys them to the directory that I specified int eh source code. But I want it so it will copy files you drag on it to the destination defined in the source code. And I want (if possable) to have it so if multiple files were draged on it, it will copy them all to teh directory.

    Sory forgot the question... Is is possible to do that? And if so how? (link or tut or somthing)

    Thank you all very much!

    Oh and was thsi board down yesterday?
    Last edited by Rune Hunter; 10-16-2004 at 05:37 PM.

  2. #2
    RoD
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    so whats the question? And yes, it was.

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    sorry I posted question in first post...

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    Code:
    int main(int argc, char* argv[]) {
    
    }
    if you drag files onto your executable the names will be in the argv array.

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    ok here is my code. Some reason it isn't working.


    Code:
    #include <iostream.h>
    #include <Windows.h>
    
    int main(int argc, char* argv[])
    {
        bool test = 0;
        
        CopyFile(
        "argv",
        "C:\\Program Files\\Game_Maker6\\lib\0",
        test
        );
    }
    Please help me...

  6. #6
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    argv is a variable....

    run this and see what happens when you drag files on to it.

    Code:
    int main(int argc, char* argv[]) {
    
      for (int i = 0; i < argc; i++) {
        cout << argv[i] << endl;
      }
      return 0;
    }

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    alright ok it worked now. but now it shows it's self as well. But I will test it a little futhur.

    Thank you lot!

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    ok so how would I transfer the string to anouther string or somthing so I can atcualy use it were I need to?

  9. #9
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    -well, if its being done in main, you can just use argv[1] to argv[n]

    -if you are using the "string" class you can do a simple assignment:
    string foo = argv[1];

    -if you are using c-strings you'll have to allocate large enough buffers statically or dynamically allocate buffers based on the string size, then you can use "strncpy()" to copy the strings value into the new buffer.

    for your purposes is seems like just using the argv[i] variable should be sufficient unless you need to alter it.

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    thats the thing, I'm not sure how to do teh argv[i]. I only know how to cout it nothing else. That is were I need help.

  11. #11
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    its a variable just like any other variable. you can use each argv[i] for i = 1 to 'argc' as a regular old c-string (1 to argc being the params passed).

    CopyFile( argv[3], "some/path/", 0 ); // copy 3rd file passed

    you might want to consider a loop (similar to how they were printed out) to copy each one.

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    I don't know I'm jsutnot getting this. Oh well.

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