C++ to C

Want to convert these C++ to C??

(1)

Code:

#include <iostream.h>
#include <iomanip.h>


// Print out the first n Fibonacci numbers. n is assumed to be >= 1.
void fibo ( int n )
{
    int current = 1;      // The value of the (i)th fibonacci number 
    int next    = 1;      // The value of the (i+1)th fibonacci number 

    cout << "\n\n\t  I \t Fibonacci(I) \n\t=====================" << endl;
    for ( int i = 1; i <= n; i++ ) {
	cout << "\t" << setw(3) << i <<  "\t\t" 
             << setw(4) << current << endl;
	int next2 = current + next;
	current = next;
	next    = next2;
     }
}

int main ( void ) 
{
    int n;        // The number of fibonacci numbers we will print 

    cout << "How many Fibonacci numbers do you want to compute? ";
    cin  >> n;
    if ( n <= 0 )
       cout << "The number should be positive." << endl;
    else 
       fibo ( n );

    return 0;
}




#include <iostream.h>

/* Get a positive integer from user */
int getPositive(void){
  int current;

  while( 1 ){
      cout << "Please enter a positive integer: ";
      cin >> current;
      if (current > 0) return current;
      cout << "It should be a positive integer";
  }
}

/* Compute GCD */
int gcd (int dividend, int divisor)
{
  int remaind;

  remaind = dividend % divisor;
  while (remaind != 0) {
       dividend	= divisor;
       divisor	= remaind;
       remaind	= dividend % divisor;
  }
  return divisor;
}

void main(void)
{
  int dividend = getPositive();
  int divisor  = getPositive();

  cout << "The GCD of " << dividend << " and " << divisor << " is "
       <<  gcd(dividend, divisor) << endl;
}

> Want to convert these C++ to C??
I don't, do you?
How about trying it for yourself.

Basically, replacing cout with printf() will get a lot of it done.

And declaring variables at the beginnig of each function.