Hw help, compiling error.

[Kazasan]

#include <iostream>
using namespace std;

void Outputgrade(double avg);
int const SENTINEL = -1;
int main()
{
int i = -1;
double num = 0, sum = 0, avg;
do
{
i++;
sum += num;
cout <<" Please enter grades in percent (0-100) or -1 to terminate: ";
cin >> num;
while( ((num < 0) || (num >100)) && (num != SENTINEL))
{
cout << "you have entered an invalid value please re-enter: ";
cin >> num;
}
}while(num!= SENTINEL);
avg = (sum/i);

Outputgrade(double avg);
return 0;
}


void Outputgrade(double avg)
{
cout << "The average score for this midterm is :";
if(avg < 50)
cout << "F";
else if (avg <= 60)
cout << "D";
else if (avg <= 70)
cout << "C";
else if (avg <= 80)
cout << "B";
else if (avg <= 95)
cout << "A";
else
cout << "A+";

}


Thats my program that calculate the midterm average in term of a,b,c...etc.
i can't compile because of the following error.
missing ')' before type double ( at Outputgrade(double avg); )
and 'Outputgrade' :function does not take 0 parameter.
anyone could help me?

[bithub]

First of all, you need to read the sticky post to learn how to use code tags.

Second, you are calling the Outputgrade function incorrectly. You dont pass a type as a function parameter, just a variable. The correct way to do it would be:

Outputgrade(avg);

[Kazasan]

First of all, you need to read the sticky post to learn how to use code tags.

Second, you are calling the Outputgrade function incorrectly. You dont pass a type as a function parameter, just a variable. The correct way to do it would be:

Outputgrade(avg);

SWEET thanks, i'll make sure i'll use the code tag next time,
i luv u man.