Thread: Help with outputing char in int

I want to output c[0] and c[1] in int , should I use type casting ( and how ? ) or atoi ( it requires casting since the proto is const char * ?)

Code:

#include <iostream>

using namespace std;
union swap_byte{
    void swap();
    void set_byte(unsigned short i);
    void show_word();
    unsigned short u;
    unsigned char c[2];
};
void swap_byte::swap()
{
    unsigned char t;
    t=c[0];
    c[0]= c[1];
    c[1]=t;
}
void swap_byte::show_word()
{
    cout<<u;
}
void swap_byte::set_byte(unsigned short i)
{
    u=i;
}
int main()
{
    swap_byte b;
    b.set_byte(49034);
    b.swap();
    b.show_word();
    cout<<b.c[1];
    cout<<b.c[0];
    
    
    int x;
    cin>>x;
    return 0;
}

Im not sure what your trying to do...

But, cout << (int)b.c[1];

should work.

If thats not what you need, try to explain exactly what you want your program to do.

Yeah, I get lost when reading your code.. I just cant figure out what your wanting to do...

If you simply just wanting to store a number into a char and then display that number

Code:

#include <iostream>

int main()
{

    unsigned char one_byte = 20;

    std::cout << (int)one_byte;

    return 0;

}

if your not against using a little c in your c++ program
this works real easy, im not sure if it will address every
problem you may come across but if it helps with the current
then yaya?, anyways :

Code:

char mystring[6] = "hello";
printf("%i  %i",mystring[0],mystring[1]);

output :

104 101