Thread: Const Char to Char Error

Originally Posted by stickman

Thanks. Now how do I add int a to blah?

int a=0;
blahblah=blahblah+a;

That would try to add a and blahblah.

Why not use the += plus/equals operator


instead of:

Code:

blahblah=blahblah+a;

could be:

Code:

blahblah += a;

The plus/equals operator is basically the string class's version of the cstring "strcat()" function.


The Brain's tip o' the day.

Sorry, I think my faq link was broken. Anyways check it out (I think the link works now). Here's code taken from the faq:

Code:

string IntToString(int num)
{
  ostringstream myStream; //creates an ostringstream object
  myStream << num << flush;

  /*
   * outputs the number into the string stream and then flushes
   * the buffer (makes sure the output is put into the stream)
   */
  
  return(myStream.str()); //returns the string form of the stringstream object
}

It's a nice little function you can use like this:

Code:

//...
int main()
{
std::string blah("Your number is: ");
int num=1;
blah+=IntToString(num);
}

Be sure to #include <sstream>

I was under the assumption that int a was already converted to string... once 'int a' becomes 'string a' then you can concantinate using plus/equals.

>>Here is the link to the FAQ for an easy example of how to stream from int to string.

I guess I wasn't making it obvious enough...Or maybe no one can hear me

since your using constant type, i believe your data already entered into the program, so why not use

[code]
#include <iostream>
#include <string>
#include <conio.h>
using namespace std;

int main()
{
string mystring = "My words here!";
cout << mystring << endl;
mystring.insert(13, " \'more words\' ", 0, 14);
cout << mystring << endl;
getch();
}
[\code]

Output :

My words here 'more words' !

Here is a link for a refrence to insert, PDF Tutorial

Here is the pseudocode for what ye' desire


1) covert 'int x' to 'string x' as per the example in the FAQ. I would probably pass int x into a function intTostring( ) for example.

Hint

Code:

string result = "The number is: ";

result += intTostring(x);

where intTostring( ) will accept an integer argument.. and will have a string type return value.



2) Your "int to string" function will at least contain this syntax.. which will perform the actual conversion:

Hint

Code:

myStream << x << flush;

3) The only thing left.. is to pick your choice of data structure that will allow you to readilly store & access your new list of strings...

Hint

Code:

string answer[10];

for( int i = 0; i < 10; i++ )

     answer[i] = result;

Hope this is somewhat close to what you are asking for

You must be tired, why don't you go to sleep and continue this conversation tomorrow?

Code:

#include <iostream>
#include <string>
#include <sstream>

std::string IntToString(int num)
{
    std::ostringstream myStream; //creates an ostringstream object
    myStream << num << std::flush;

    /*
    * outputs the number into the string stream and then flushes
    * the buffer (makes sure the output is put into the stream)
    */
  
    return(myStream.str()); //returns the string form of the stringstream object
}

int main()
{
    std::string blah("Your number is: ");
    std::string arr[10];
    
    for (int x = 0; x <10; x++)
    {
        arr[x] = blah + IntToString( x );
    }

    for (int x = 0; x <10; x++)
    {
        std::cout << arr[x] << '\n';
    }

    return 0;
}