how do i pass arguments to a function^^^please help

i need to write a program which opens a file in a function, not in main, and open it from dos command...

ive writen the program to open it in main but im not aloud to do that i have to make a seperate function for opening a file

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h> 

int main(int argc, char* argv[])
{
	
	FILE * in;
	int c;
	int num;
	int count = 0;
	

	in = fopen(argv[2],"r");
	num = atoi(argv[1]);

	while((c = fgetc(in)) != EOF) {

		if(count < num) {
			fputc(c, stdout);
			count++;
		}
		else {
			fprintf(stdout,"\n");
			count = 0;

		}

	}

	return 0;
}

my question is how do i go about passing the arguments to the function after declaring them in the main....

thanks guys

I see plenty of parameters being passed to plenty of functions already.
Just write a function and call it in pretty much the same way as you're doing now.

you have already written a function main()... just do the same except name it something else and pass in something different inside the ().

Code:

MyFunction1(Param1, Param2);      // Calls MyFunction1() and passes-in variables Param1 & Param2
A = MyFunction2(X, Y);     // Calls MyFunction2() and copies the return value into variable A

Check-out the Function Tutorial. And, re-read the chapter in your book that introduces functions. You have a book right?

Functions can be confusing because you will have to write it at least three times, in slightly different form... 1-the function protototype, 2- the function definition, 3-each time you call the function.

Most functions require parameters. Some don't. Some functions return a value. Some don't.

Take the time to make sure that you understand functions. Everything in C++ is done with functions!