Newb Question - Cant convert Char[41] to Char

This is a discussion on Newb Question - Cant convert Char[41] to Char within the C++ Programming forums, part of the General Programming Boards category; Hi All, I am new to this forum and to C++ programming. But still I have managed my program to ...

  1. #1
    Registered User
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    Aug 2004
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    1

    Question Newb Question - Cant convert Char[41] to Char

    Hi All,

    I am new to this forum and to C++ programming. But still I have managed my program to error .

    Can someone tell me what is wrong with this code?!

    Code:
    void main()
    {
    	char User[UserMaxLength];
    	print_header();
    	User = get_user();
    	printf("%s@!localhost [#]", User);
    	return;
    }
    
    char get_user()
    {
    	char Temp[UserMaxLength];
    	scanf("Gebruikersnaam: %s", &Temp);
    	return Temp;
    }
    The error I get is:
    Code:
    C:\Program Files\Microsoft Visual Studio\MyProjects\Kernel\KK006b\KK006b.cpp(16) : error C2440: '=' : cannot convert from 'char' to 'char [41]'
            There are no conversions to array types, although there are conversions to references or pointers to arrays
    C:\Program Files\Microsoft Visual Studio\MyProjects\Kernel\KK006b\KK006b.cpp(31) : error C2440: 'return' : cannot convert from 'char [41]' to 'char'
            This conversion requires a reinterpret_cast, a C-style cast or function-style cast
    Any help would be greatly appreciated

    Kalkran

  2. #2
    Registered User manofsteel972's Avatar
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    Mar 2004
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    317
    Your return type is char. You are trying to return an array. the types dont' match so your getting an error. You want to return a pointer to the array.
    "Knowledge is proud that she knows so much; Wisdom is humble that she knows no more."
    -- Cowper

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    Compilers=gcc 3.2.3, Visual C++ 6.0, DevC++(Mingw)

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  3. #3
    the hat of redundancy hat nvoigt's Avatar
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    As a start, use "int main()" not "void main()". If you need an explanation, have a look at the FAQ.

    You cannot assign an array this way. For simplicity, I would suggest passing the array you need your data in to your get_user function and removing the temp variable.
    hth
    -nv

    She was so Blonde, she spent 20 minutes looking at the orange juice can because it said "Concentrate."

    When in doubt, read the FAQ.
    Then ask a smart question.

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