Thread: I need a type of variable that uses however much range needed

I really dont completely understand what you want to do...

So you want to take a number and turn it into the ASCII equivalent?

an int is 32bits long I believe, and if thats too much..

how bout a char or unsigned char

If I am completely missing the point, I am sorry, try talking to me like im 2

I think I understand what you are trying to do.

Say the user inputs 8 billion, well its too large to store in 32 bits.

How about using std::string to store the number it will be one of the easist to resize as needed

btw an int is not always 32 bits.

Originally Posted by Thantos

btw an int is not always 32 bits.

Ah, really, I suppose its compiler dependant?

IIRC here are guidelines in the standard but they specify the min values. The max values are set by the compiler and the system

If you mean converting the int value of a string to char form, I understand Heres a way I used for it.

Make two functions. One will tell the program how many int values to input, and the other, run by the first, will convert it. ie:

Code:

void convert(int length, ...) {
  va_list arguments;
  va_start(arguments, length);
  for (int x=0; x<length; x++){
    std::cout<<(char)va_arg(arguements, int);
  }
  va_end(arguments);
}

void itos(int argn) {
  if (argn == 1) convert(ary[0], ary[1]);
  if (argn == 2) convert(ary[0], ary[1], ary[2]);
  .
  .
  .
}

The array is the message broken up. [0] is the amount of chars, inother words when declaring itos(int to string) use ary[0] for its declare so it uses the right amount. Everything after [0] is the individual chars in int form. I just did this earlier myself