Thread: cannot call another function error

i get error

Code:

sexy.cpp: In member function `void sexy::setOutput(sexyt::Type,
   bool)':
sexy.cpp:19: error: no matching function for call to `search(
   sexyt::Type&)'

for this code
this is sexy.cpp

Code:

#include "mate.h"
void sexy::kiss(sexyt::Type t, bool status) {
        if(status)
        {
                search(t);                                              
        }
        else
        {

        }
}

and this is mate.cpp

Code:

void mate::search(sexyt::Type t) {
     /*blah blah code*/
}

according to your your error, it's looking for Type reference, so my guess is that your mate.h has search defined as such:

Code:

void mate::search(sexyt::Type & t);

where as your definition in the cpp leaves out the reference. That's the first thing I would check to fix this problem. There could be some other things, but that's top of the list.

i have defined it as

Code:

void mate::search(sexyt::Type t);

do both mate and sexy have access to Type? Meaning, is Type declared in the public field of sexyt?

ok this is what i have

Code:

class mate {
 public:
        void search(sexyt::Type t);
 private:
        class Node {
                public :
                        Node* nextPtr;
                        sexyt::Type t;
        };

and in the mate class
i have
#include "mate.h"

I'm assuming you have included sexyt.h in your mate.h file. If not, that would be a problem. It might not like the fact that you have a data member named t, and a formal parameter of the search function named t.

I also just noticed that it's not ........ed off about your kiss function, it doesnt like setOutput where ever that may be....so we've been barking up the wrong tree.

searchLL is a member function of mate. sexy::setOutput cannot see searchLL because it is not declared in the global namespace, so the compiler correctly assumes that it does not exist.