cannot call another function error

This is a discussion on cannot call another function error within the C++ Programming forums, part of the General Programming Boards category; i get error Code: sexy.cpp: In member function `void sexy::setOutput(sexyt::Type, bool)': sexy.cpp:19: error: no matching function for call to `search( ...

  1. #1
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    cannot call another function error

    i get error
    Code:
    sexy.cpp: In member function `void sexy::setOutput(sexyt::Type,
       bool)':
    sexy.cpp:19: error: no matching function for call to `search(
       sexyt::Type&)'
    for this code
    this is sexy.cpp
    Code:
    #include "mate.h"
    void sexy::kiss(sexyt::Type t, bool status) {
            if(status)
            {
                    search(t);                                              
            }
            else
            {
    
            }
    }
    and this is mate.cpp
    Code:
    void mate::search(sexyt::Type t) {
         /*blah blah code*/
    }

  2. #2
    vae victus! skorman00's Avatar
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    according to your your error, it's looking for Type reference, so my guess is that your mate.h has search defined as such:
    Code:
    void mate::search(sexyt::Type & t);
    where as your definition in the cpp leaves out the reference. That's the first thing I would check to fix this problem. There could be some other things, but that's top of the list.

  3. #3
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    i have defined it as
    Code:
    void mate::search(sexyt::Type t);

  4. #4
    vae victus! skorman00's Avatar
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    do both mate and sexy have access to Type? Meaning, is Type declared in the public field of sexyt?

  5. #5
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    ok this is what i have
    Code:
    class mate {
     public:
            void search(sexyt::Type t);
     private:
            class Node {
                    public :
                            Node* nextPtr;
                            sexyt::Type t;
            };
    and in the mate class
    i have
    #include "mate.h"

  6. #6
    vae victus! skorman00's Avatar
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    I'm assuming you have included sexyt.h in your mate.h file. If not, that would be a problem. It might not like the fact that you have a data member named t, and a formal parameter of the search function named t.

    I also just noticed that it's not ........ed off about your kiss function, it doesnt like setOutput where ever that may be....so we've been barking up the wrong tree.

  7. #7
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    hrm i changed the name of hte function to searchLL and i got a different error..
    Code:
    /*mate.h*/
    
     public:
            void searchLL(M::Type ty);
    
     private:
            class Node {
                    public :
                            M::Type t;
            };
            int count;
    };
    
    /* mate.cpp */
    void mate::searchLL(M::Type ty) {
    
    }
    
    
    
    /*sexy.cpp*/
    #include "mate.h"
    
    void sexy::setOutput(M::Type ty, bool status) {
            if(status)
            {
                    searchLL(ty);                                             
            }
            else
            {
    
            }
    }
    getting the error
    Code:
    mate.cpp: In member function `void mate::setOutput(M::Type,
       bool)':
    mate.cpp:20:  error: `searchLL' undeclared (first use this function)
    mate.cpp:20: error: (Each undeclared identifier is reported only once for
       each function it appears in.)
    Last edited by paperbox005; 08-02-2004 at 06:45 AM.

  8. #8
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    searchLL is a member function of mate. sexy::setOutput cannot see searchLL because it is not declared in the global namespace, so the compiler correctly assumes that it does not exist.

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