I am writing a function that takes two coordinates, then calculates the points in between and draw the line.

The coordinates represent points in my array, the array is viewed by a print comand that prints it into a grid in console.

The function works,

output on

0,2 -> 3,9 in a 10 by 10 grid would look like

0000000000

0000000000

1000000000

1000000000

0100000000

0100000000

0100000000

0010000000

0010000000

0001000000

I'm wondering if i am doing this properly, or if there would be a better way to do it.

Links to similar functions or the code to them would help, trying to learn how best to do this

my code- i commented as best i could

Thanks for your timeCode:void Line(int xs, int ys, int xe, int ye, int vl, int* array) { // first calculate slope using rise/run float oy; // store last y coord bool first = true; // to handle first time in loop if (xe != xs) // can't have a slope of infinity { float s = ((float)ye - (float)ys) / ((float)xe - (float)xs); // slope float b = ys - ((float) xs * s); // the B in the equation y = ax + b for( float c = float(xs); c <= (float)xe; c++) // drawing loop { float y = (c * s) + b; // calculate the y if ( (y + .5) >= ceil(y) ) // means it was x.5 or greater { y = ceil(y); // round up } else { y = floor(y); // its less then x.5 so round down } if (first) // first time in the loop { write(c, (int)y, vl, array); oy = y; first = false; } else // not first time in loop { for( int ty = oy ; ty < y; ty++) // draw from last coord, draw line towards next y, stop 1 before { write(c - 1, ty, vl, array); } oy = y; } } // last point, should be xe, ye write(xe, ye, vl, array); } }