Converting a float to an int without truncation
Hello, I am in my first two weeks of a C++ class and I am having a problem with my program.
my program is supposed to accept five decimal numbers from the keyboard. Once these five decimal numbers are entered I must convert them into the "nearest integer" .
I have played around with several "casting" procedures but all of them simply truncate (drop) the number after the decimal.
I have grown frustrated and I need help.
To whoever reads this, thanks for your time, it is greatly appreciated!!
giveand x has some value:Code:float x; int y;
Edit: Provided that the number is positive. If negitive just do the reverseCode:y = (int)x; y-=x; if ( y >= 0.5 ) x++;
Last edited by Thantos; 06-15-2004 at 11:07 PM.
>I have played around with several "casting" procedures
Add 0.5, then do the casting. You could put this code into a function.
Originally Posted by swoopy
This did the trick!!
Adding 0.5 was just what I was looking for!
I knew I had to solve this problem with a little math but I guess I was just thinking a little to deep to see such a simple fix!!
swoopy rules!!!
