Need help understanding !NOT

Good afternoon everyone.

I have a simple assignment statement:

var=((5*67)+!50)

My problem is understanding the ! (NOT). If something is not 50, it is false, which returns a value of 0. I would calculate var=335. Is this correct? I know the !50 is a logical operation, which I read as returning TRUE or False. My difficulty is converting that T/F return value (0 or 1) and using it as part of an arithmetic calculation. Is there some place I can read up on this to help grasp the concept?

Thanks for your help

Umm... Will this do it for you?

Code:

int convert(bool in) {
   return ((in) ? 1 : 0);
}

!0 is 1
! of anything which isn't zero is 0

Imagine !x as if ( x == 0 )

Originally Posted by nickadeemus2002

Good afternoon everyone.
var=((5*67)+!50)

Code:

var = ((5*67)+!50);
var = ((5*67)+0);

Are the same. Indeed your example is just a waste of code since you would normally just do

Code:

var = 335; // as you had previously mentioned

You should use the ! operator with variables, not constants.

Code:

var = !x; // acceptable code
var = !0; // code that only will generate confusion later.

There is nothing wrong with using ! with constants except for the fact that it obfuscates your code.