Is is safe to do so?Code:char* stupid = getenv("HOME"); string filepath = stupid; cout << "Your home directory are " << filepath << endl;
I have to use char pointer because compiler complain if I use char array because compiler cannot know the size of char array. I mean, I have to be very careful if I have to deal with pointer.
so
string = char pointer;
Is it safe??????
Or is there a better way inisialize string c++-style from string c-style?
A man asked, "Who are you?"
Buddha answered, "I am awaked."
>> safe to do so?
No, but only because getenv() might return NULL.
You could do something like this instead:
ggCode:char* stupid = getenv("HOME"); string filepath = (stupid == NULL) ? "[not set]" : stupid; cout << "Your home directory is " << filepath << endl;
Code:cout << "Your home directory is " << getenv("HOME") << endl;
Wrong.
It is illegal to insert a NULL C-string pointer into an ouput stream.
gg
Oh, okay. I've never tried that, I just assumed.
Upon saying that, I decided to try:
It didn't core dump on me ("HOM" is a nonexistant variable), nor did I get compile time errors/warnings.Code:1 #include <iostream> 2 #include <unistd.h> 3 4 int main() 5 { 6 std::cout<<getenv("HOM")<<std::endl; 7 return 0; 8 }
Had to look it up myself, 27.6.2.5.4 - 3
gg
You're putting too much faith in your std::lib implimentation.....just go to the source if you need to verify something
gg
Thanks for that link. =)
Well, actually this example is to simplify my problem. The problem is.....Originally Posted by Russell
I have this function:
void myFunctionThatOnlyAcceptStringArgument( string HomeDirectory );
And the string HomeDirectory is taken from this function:
getenv("HOME");
You know, I make a C++ program that have to deal with system. So I have to mix C code ( to deal with system, you know system programming use char* string not C++ style string ) and C++ code ( the program it self ).
Thank you............ and thank for Codeplug
A man asked, "Who are you?"
Buddha answered, "I am awaked."
