Thread: adding odd numbers only

  1. #1
    cout<<"Wakka Wakka"<<endl
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    May 2004
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    adding odd numbers only

    Hello all,

    Im new here and was hoping to get a bit of help with a program i am writing for class. The program has the user enter a start number then a ending number. Then displays only the Odd number. Ive been successful up to that point. The next part has been giving me a bit of a headache. Can you help?

    After the odd numbers are displayed the program needs to Add those numbers together and display the sum. So if the user enters in 1 and 10 it will display 1,3,5,7,9 then 25 for the total sum. Any guidance would be much appreciated and I hope to hang around here and help anyone that might need it in the future.


    Code:
    #include <iostream.h>
    #include <ctype.h>
    #include <math.h>
    
    void main()
    {
    	char doAgn = 'Y';
    	int startNum= 0;
    	int endNum = 0;
    	int oddCount = 0;
    	int sum = 0;
    	int sumNum = 0;
    	
    
    	while (toupper(doAgn) =='Y'){
    
    		//get inputs
    
    		cout<<"Please enter the beginning number:";
    		cin>>startNum;
    
    		cout<<"Please enter the ending number:";
    		cin>>endNum;
    
    		//display the odd numbers
    		
    		for (int i = startNum; i < endNum; i++){
    			oddCount++;			
    			if(oddCount % 2 !=0)
    			cout<<oddCount<<endl;
    		}//end For
    
    		//display the total sum for the odd numbers displayed
    
                    ????????
    
    		//display the average for all the odd numbers displayed
    
                    //hopefully i will grasp this after understanding the above line of code.
    
    			
    
    		//clear out odd count 
    		oddCount = 0;
    
    	}//end while
    
    
    }//end main

  2. #2
    vae victus! skorman00's Avatar
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    keep track of the sum in a variable. Keep on adding to it whenever you find an odd number

  3. #3
    cout<<"Wakka Wakka"<<endl
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    thats what i figured needs to happen. The problem for me is how do i code after the (oddCount % 2 !=0) finds the odd number once then again "then make those two numbers add" up that I can store in a variable. thanks for the point in the right direction skorman00.

  4. #4
    vae victus! skorman00's Avatar
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    if that test comes out to true, you know you have an odd number right? In addition to displaying it, also add it to the running sum.

  5. #5
    Registered User
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    You wrote:

    for (int i = startNum; i < endNum; i++){
    oddCount++;
    if(oddCount % 2 !=0)
    cout<<oddCount<<endl;

    Try this:-

    for (int i = startNum; i < endNum; i++)
    {

    if(oddCount % 2 !=0)
    {
    oddCount++;
    cout<<oddCount<<endl;
    }
    }

    Hope this helps,

    BigSteve
    bigSteve

  6. #6
    cout<<"Wakka Wakka"<<endl
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    thank you for your help. I'll keep thinking this one through

  7. #7
    cout<<"Wakka Wakka"<<endl
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    oh i see bigSteve let me try that real quick

  8. #8
    cout<<"Wakka Wakka"<<endl
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    well now that doesnt display my oddCount ... i guess this is one to sleep on or something

  9. #9
    vae victus! skorman00's Avatar
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    that threw you into an infinite loop. You only incrimented oddCount if it was odd, so it would just stop incrimenting if it became even. I'll now point out that you are using oddCount to keep track of the odd numbers, which starts at 0, not the number you got from the user. Keep track of that with i instead, which you have set up properly.

  10. #10
    Registered User biosx's Avatar
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    What is the point of oddCount?

    Here is some pseudo-code/logic to your program. I hope it helps.

    Code:
    while still getting input
    {
            declare total variable
     
            get starting number
            get ending number
    
            for i = from starting-number to ending-number
            {
                    if i is an odd number
                    {
                            print i
                            total += i 
                    }
            }
    
             print total
    }

  11. #11
    cout<<"Wakka Wakka"<<endl
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    Thanks peoples for the help. My c++ book doesnt have a thing about the += operator in it Thats what was causing me the problems. How would you achieve the same effect without it?

  12. #12
    C++ Witch laserlight's Avatar
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    total = total + i
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  13. #13
    cout<<"Wakka Wakka"<<endl
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    thanks laserlight

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