fastest way to change a time_t into a string

This is a discussion on fastest way to change a time_t into a string within the C++ Programming forums, part of the General Programming Boards category; i need to change the string of numbers returned by time() (in a time_t type variable) into a string type ...

  1. #1
    Registered User whackaxe's Avatar
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    fastest way to change a time_t into a string

    i need to change the string of numbers returned by time() (in a time_t type variable) into a string type varaible. what is the best way to do this?

  2. #2
    Yes, my avatar is stolen anonytmouse's Avatar
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    ctime() or strftime() via localtime() or gmtime() if you need more control.

  3. #3
    Registered User major_small's Avatar
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    http://cppreference.com/stddate.html

    more detail on the above functions
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  4. #4
    & the hat of GPL slaying Thantos's Avatar
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    strftime() is a better choice than ctime() or asctime() simply because ctime() and asctime() return a pointer to a local static buffer that will be overwritten during each subquent call. Of course if you are only dealing with one date then thats perfectly fine

  5. #5
    Registered User whackaxe's Avatar
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    i don't think you understood what i meant. time returns time_t which contains the number of seconds since 1/1/1970 i need to convert that number into a string (just the same thing, but i need it as a string type). sorry for late reply

  6. #6
    & the hat of GPL slaying Thantos's Avatar
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    sprintf() is the easist way
    Code:
    sprintf(buffer, "%u", (unsigned) time(NULL));
    Where buffer of course is an array of characters.

  7. #7
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    Quote Originally Posted by whackaxe
    i don't think you understood what i meant. time returns time_t which contains the number of seconds since 1/1/1970 i need to convert that number into a string (just the same thing, but i need it as a string type). sorry for late reply
    Such an operation is inherently nonportable. time_t is an arithmetic type, but the only operation defined for it is a comparison to (time_t)-1. So any integer-string conversions would be relying on a specific representation of time_t. However, because most implementations use unsigned long or similar, sprintf should work.
    Code:
    time_t present = time(0);
    sprintf(buffer, "%lu", (unsigned long)present);

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