Compiler Problem

sitestem · 04-11-2004, 03:28 PM

Hi all,

I have just started on C++ and am trying to follow the tutorials on this site. However, I've bumped into a problem. I'm doing the example where the user enters a number and then it is returned. Here is my code.

Code:

#include <iostream.h> 
int
main() 
{ 
  int thisisanumber; 
  cout<<"Please enter a number:";
  cin>>thisisanumber; 
  cout<<"You entered: "<<thisisanumber;
  cin.get();
  return 0; 
}

When I enter my number and press return, the compiler just closes. I've put cin.get(); in, like explained in a tutorial.

Would it be possible for somebody to help? I've looked in the FAQ but couldn't find anything. I am using Bloodshed.

Thanks very much,
Mike

**Prelude** · 04-11-2004, 03:45 PM

Your use of cin leaves a newline in the stream that cin.get() picks up. The easy solution is to add another cin.get(). A somewhat better solution is to use cin.ignore() with a large enough size to handle any length of extraneous input and a delimiter of '\n'. The best solution is to only use getline to read input as a string and then perform conversions once you have the data in memory. Here is one hybrid approach:

Code:

#include <iostream> 
#include <string>
#include <cstdio>

using namespace std;

int
main() 
{
  string buffer;
  int thisisanumber; 
  cout<<"Please enter a number:";
  getline ( cin, buffer );
  sscanf ( buffer.c_str(), "%d", &thisisanumber );
  cout<<"You entered: "<<thisisanumber;
  cin.get();
  return 0; 
}

And a more C++ish approach using stringstreams:

Code:

#include <iostream>
#include <string>
#include <sstream>

using namespace std;

int
main() 
{
  string buffer;
  int thisisanumber; 
  cout<<"Please enter a number:";
  getline ( cin, buffer );
  istringstream iss ( buffer );
  iss>> thisisanumber;
  cout<<"You entered: "<<thisisanumber;
  cin.get();
  return 0; 
}

sitestem · 04-11-2004, 03:48 PM

Yup, works a treat. Thanks Prelude

04-11-2004, 03:28 PM	#1
sitestem Registered User Join Date: Apr 2004 Posts: 14	Compiler Problem Hi all, I have just started on C++ and am trying to follow the tutorials on this site. However, I've bumped into a problem. I'm doing the example where the user enters a number and then it is returned. Here is my code. Code: #include <iostream.h> int main() { int thisisanumber; cout<<"Please enter a number:"; cin>>thisisanumber; cout<<"You entered: "<<thisisanumber; cin.get(); return 0; } When I enter my number and press return, the compiler just closes. I've put cin.get(); in, like explained in a tutorial. Would it be possible for somebody to help? I've looked in the FAQ but couldn't find anything. I am using Bloodshed. Thanks very much, Mike
sitestem is offline

04-11-2004, 03:45 PM	#2
Prelude Code Goddess Join Date: Sep 2001 Posts: 9,661	Your use of cin leaves a newline in the stream that cin.get() picks up. The easy solution is to add another cin.get(). A somewhat better solution is to use cin.ignore() with a large enough size to handle any length of extraneous input and a delimiter of '\n'. The best solution is to only use getline to read input as a string and then perform conversions once you have the data in memory. Here is one hybrid approach: Code: #include <iostream> #include <string> #include <cstdio> using namespace std; int main() { string buffer; int thisisanumber; cout<<"Please enter a number:"; getline ( cin, buffer ); sscanf ( buffer.c_str(), "%d", &thisisanumber ); cout<<"You entered: "<<thisisanumber; cin.get(); return 0; } And a more C++ish approach using stringstreams: Code: #include <iostream> #include <string> #include <sstream> using namespace std; int main() { string buffer; int thisisanumber; cout<<"Please enter a number:"; getline ( cin, buffer ); istringstream iss ( buffer ); iss>> thisisanumber; cout<<"You entered: "<<thisisanumber; cin.get(); return 0; } __________________ My best code is written with the delete key.
Prelude is offline

04-11-2004, 03:48 PM	#3
sitestem Registered User Join Date: Apr 2004 Posts: 14	Yup, works a treat. Thanks Prelude
sitestem is offline

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