Thread: String Copying Probleming

  1. #1
    Registered User
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    String Copying Probleming

    Hello,

    i'm trying to copy a const char* string (call it stringA) to a char* string (stringB).

    now lets say stringA is 20 characters long and i only want to copy 10 of those characters to stringB. Whats the best possible way to go about doing it?

    i've tried using a for loop..

    Code:
    int i;
    for (i=0; i < 10; i++)
    {
         stringB[i] = stringA[i];
    }
    stringB[i] = '\0';
    ... but this only results in a segmentation core fault.

    then i tried using strncpy...

    Code:
    strncpy(stringB, stringA, 10);
    .. but this isnt giving me the results i want. its copying the whole stringA into stringB.

    what am i doing wrong? Any help would be great.

    Thanks.

  2. #2
    S Sang-drax's Avatar
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    Could you post a complete program that isn't working? Your examples looks correct.
    Last edited by Sang-drax : Tomorrow at 02:21 AM. Reason: Time travelling

  3. #3
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    If stringB is declared like this:
    char* stringB;
    then you need to allocate memory with new.

    Or declare it with at least 11 characters like this:
    char stringB[11];

  4. #4
    Registered User major_small's Avatar
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    May 2003
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    since it looks like you're using C-style strings, don't forget to add the '\0' at the end of the loop... most likely you're trying to write to space you never allocated...

    this code compiles fine:

    Code:
    #include<iostream>
    
    int main()
    {
    	int i;
    
    	const char*stringA="This String is more than 10 characters long";
    	char*stringB=new char[11];
    
    	for(i=0;i<10;i++)
    	    stringB[i]=stringA[i];
    	stringB[i]='\0';
    
    	std::cout<<stringA<<std::endl<<stringB<<std::flush;
    
    	std::cin.get();
    	return 0;
    }
    don't forget to delete stringB when you're done with it too...
    Last edited by major_small; 04-08-2004 at 11:04 AM.
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