Getting class info through a pointer

**Drakon** · 04-07-2004

I have a pointer that points to a class. How do I get class members through the pointer?

example:

Code:

class TestClass
{
public:
          int Num;
};

void main()
{
          TestClass TC;
          TC.Num = 5;
          TestClass *TCPointer;
          TCPointer = TC;
          
          cout << TCPointer.Num;
}

Problem is, I can't have TCPointer.Num - I can only have TCPointer. As I write this, I found I way I don't need to do it anymore, but is this possible to do?

**Prelude** · 04-07-2004

You assign the address of an object with the address-of operator. You can then access the members of that object through the pointer with the arrow operator:

Code:

class TestClass
{
public:
          int Num;
};

int main()
{
          TestClass TC;
          TC.Num = 5;
          TestClass *TCPointer;
          TCPointer = &TC; // Address-of operator
          
          cout << TCPointer->Num; // Arrow operator
}

**jverkoey** · 04-07-2004

Code:

class TestClass
{
public:
int Num;
};
 
void main()
{
TestClass TC;
TC.Num = 5;
TestClass *TCPointer;
TCPointer = TC;
 
cout << TCPointer.Num;
}

use TCPointer->Num;

and to assign TC to TCPointer, you need to do: TCPointer=&TC

-edit-
meh, prelude you beat me, i had to eat my soop!!

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