returning a constructor?

//hi i saw an example of the + operator overloaded and i see that that operator+ function returns a constructor what is the logic behind this?

Code:

---


Class MyClass{
      public:                 
          MyClass(int);//constructor   
            ... 
          //+ operator overloaded
          MyClass operator+(const MyClass &objetc)const
        {
            //how this can work and why?
              return MyClass(localData + object.localData)
        }
          ...
};

int main()
{
    MyClass n1;
    MyClass n2(20);
    Mclass n3(6);
       
    n1 = n2+n3;
    return 0;
}

---

thanks for any help

It's a form of optimization. In the code you have listed you can return anything that resolves to a MyClass object. Clearly, the MyClass constructor will return a MyClass object which can then act as the return object for + operator. It's sort of like using isalpha() in the following syntax:

Code:

---

char myString[] = "hello world";
char ch;
for(int i = 0; i < strlen(myString); ++i)
{
  if(isalpha(ch))
        cout << "element " << i << " of myString is a letter" << endl;
  else
        cout << "element " << i << " of myString isn't a letter" << endl;
}

---

here, isalpha() returns a value that can be interpretted as true or false, which is what if() is looking for, so it works just fine.

good ,
thanks