Thread: Bitwise Explanation in the Form of a Question

Bitwise AND adds bits together, and if two 1's line up, it's a 1, otherwise, it's a 0, like so, yes?

Code:

  0011
& 1010
= 0010

So, in an if statement:

Code:

int y=2; //0010
if (y & 3)//0011
{
cout<< "This is true.";
}

So that means if just one of the resulting bits is 1, the condition is true?

So saying if (y & 3) is the same as saying if (y==1 || y==2 || y==3), yes?

>> So that means if just one of the resulting bits is 1, the condition is true?
Zero if false, everthing else is true.

>> So saying if (y & 3) is the same as saying if (y==1 || y==2 || y==3), yes?
Yep.

>> Bitwise AND adds bits together...
Not really "adds", rather "both have to be 1 to get a 1".

gg