ctrl-d problem

Hey what's goin guys?

OK I got a real quick question for you all that has been bothering me. How can I get the EOF (or ctrl-d) to work on my C++ program. I know in C you can use getchar, but I am using integers as input on this program.

Any advice/hints on how to fix this?

Code:

 #include<iostream.h>
#include<stdio.h>

void print( int min2, int max2, int n=5);	//Declaration

int main()
{
//	system("clear");
	
	int q=0, j=0, y=0, min=0, middle=0, max=0;

	cout<< "\n\t-This program prints out the default and middle amount of numbers-";
	
	cout<< "\n\n\tEnter (<ctrl-d> <return>) to quit the program.\n";
	
	cout<< "\n\n\tEnter three numbers with spaces: ";
	cin>> q >> j >> y;
	fflush(stdin);
	
	while( q != !EOF )
	{

	if( q > j)			//Checks for max value
	{
		if(q > y)
			max = q;

		else
			max = y;

	}

	else
	{
		if(j > y)
			max = j;
		else
			max = y;
	}

	
	if( q < j)				//Checks for min value
	{
		if(q < y)
			min = q;

		else
			min = y;

	}

	else
	{
		if(j < y)
			min = j;
		else
			min = y;
	}

	
	if ( max == q )				//Uses max & min to find middle 
	{
		if ( min == y )
			middle = j;
		else
			middle = y;
	}

	if ( max == y )
	{
		if( min == q)
			middle = j;

		else
			middle = q;

	}

	else if( max == j)
	{
		if ( min == q )
			middle = y;
		else
			middle = q;
	}

	cout<< "\n\tUsing default line-set (5)";
	cout<< "\n\tPrint 5 per line...\n";
	print(min, max );			//Use print function with default line-set

//	system("sleep 3");
	cout<< "\n\n\tNext line-set...";
	
	cout<< "\n\tUsing line-set " << middle;
	cout<< "\n\tPrint " << middle << " per line...\n";
	print(min, max, middle);	//Use print function with middle as line-set

	cout<< "\n\n\tEnter three numbers with spaces: ";
	cin>> q >> j >> y;
	fflush(stdin);
	
	}

	printf("\n\n\tPress enter to exit...\n");
	getchar();

return 0;
}

void
print( int min2, int max2, int n)			//Definition
{
	int count=0;

	cout<< "\n\t";
	
	for( int i = min2; i <= max2; i++)
	{
			cout<< i << " ";
			count++;

			if (count == n)		//Checks for new line
			{	
				cout<< "\n\t";
				count=0;
			}
    }

	cout<< "\n";
}

CJ

Code:

while( cin>> q >> j >> y )

If cin fails then either end of file was reached or an input error occurred. You can test for that after the loop body and respond accordingly. Otherwise the loop will proceed normally.

Thank you very much Prelude.

I was trying:

Code:

 while( cin.eof )

also after I posted this. However it gave off the same results. I looked in my C++ book and says it is suppose to reconize EOF, but for some reason didn't work either.

Well thanks again!

CJ

>while( cin.eof )
The correct (syntactically at least) way would be:

Code:

while ( !cin.eof() )

But this member function was not designed to be used as a loop condition and you will end up processing the last piece of input twice. Whenever possible, make it so that the call for input is the loop condition so that a success/failure return value can be used to determine whether to iterate again or to terminate the loop.