Thread: overloaded operators

You shouldn't be returning the argument after the += operator; you should return the lefthand argument.

a +=b;
should return a after b is added to it.

Originally posted by jccharl
Here is the function header

const char* operator+=(const char [])

What I am having trouble with is, I need to return to array that this function receieves as an argument, so i need to return the part after the += sign, I have tried everything I could think of, any help would be great.

Thanks

You can't overload operators that work with just built-in types as you are attempting. You'd have to encapsulate at least one of those arrays in a class and then overload operators for that, otherwise it can't be done.