Thread: *char comditional matching problem

  1. #1
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    Mar 2004
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    *char comditional matching problem

    let's say this code:


    Code:
    	
    char bufferx[] = "abc~defghi"
    
    
    char buf[111];
    
    char *a_full_parm(const char *bufferx)
    {
    	int i =0;
    	int j = 0;
    	int bkm;
    
    
    
    
    	for(i=0; i< 256; i++)  
    	{
    		if (bufferx[i] == '~')
    		{
    			bkm= i;
    			for(j=0; j < bkm ; j++)
    			{
    				buf[j] = bufferx[j];
    
    
    			
    			}
    			buf[j] = '\0';
    
    
    
    			return buf;
    		}
    	}
    }

    how i need to match it


    if (full_parm(buffer ) == "abc") <=== BIG PROBLEM
    {do something}

    BIG PROBLEM :
    but i cant match it coz itz not exactly the same??
    do i need to do casting??
    how do i go about doing the matching to "abc" here?

  2. #2
    and the hat of int overfl Salem's Avatar
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    Read about strcmp() in your manual pages
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
    Confused Magos's Avatar
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    Or use std::string, since it has overloaded the == and != operators.
    MagosX.com

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  4. #4
    vae victus! skorman00's Avatar
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    you can't compare a char* to a hardcoded string in this fashion. Your logic is right, but things aren't happening as you would like them to.

    Take Salem's advice.

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