Conversion problem, apparently.

Code:

#include <iostream>
#include <cstdlib>
#include <cstring>
using namespace std;

char output[20] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

char reverseorder(const char *input)
{

for(int a = strlen(input); a>=0; a--)
{
strcat(output, input[a]); //what the hell, man? 
input--;                   //invalid
}                         //conversion from `const char' to `const char*'
return *output;
}


int main()
{

char input[20] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

cout << "Put in something of less than /n 20 characters, chap" << endl;
cin >> input;
cout << reverseorder(input) << endl;

return 0;

}

"invalid conversion from `const char' to `const char*"

What's up with that?

>strcat(output, input[a]); //what the hell, man?
strcat takes a string as the second parameter but input[a] is just a single character. Try this instead:

Code:

char *reverseorder(const char *input)
{

  int i = 0;
  for(int a = strlen(input) - 1; a>=0; a--)
  {
    output[i++] = input[a];
  }
  return output;
}

Thanks a lot. I modified

Code:

output[i++] = input[a];

to

Code:

output[i] = input[a];
i++;

and i got somewhat of the desired result . . . except, when I run the program then, it goes up until the first whitespace and then it prints no more. How can I include whitespace?

to include whitespace in the variable input you need to accept user entry using getline() function, not >> operator.

cin.getline(input, 20, '\n');

would be a typical syntax though

cin.getline(input, 20);

would be essentially the same, as the last parameter defaults to newline char anyway.

You need to be careful when using both >> and getline() in the same program, however, as there is an issue regarding different methods of handling input under those circumstances. You can look up the topic by searching the board.

Thank you very much. It worked. I'll search the board more, though. Thank you.