The Game of Life problem

This is a discussion on The Game of Life problem within the C++ Programming forums, part of the General Programming Boards category; Hey, I have an assignment called the Game of Life. If you haven't heard of it, feel free to look ...

  1. #1
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    Jun 2003

    The Game of Life problem

    Hey, I have an assignment called the Game of Life. If you haven't heard of it, feel free to look it up. Anyway, the problem I am having is the algorithm I have to compute if the living cell has any neighbors is not producing anything. I know that the code is a little redundant but if you have any suggestions, please help.

    This code basically goes through the array and adds up all the neighbors and if they are less than 2 or more than 3, then the current node is dead(i.e. 0)
    Here is the code:

    void liveon(int g1[][22],int g2[][22])
    for(int r=0;r<22;r++)
        for(int c=0;c<22;c++)
         if(g1[r-1][c-1]+g1[r-1][c]+g1[r-1][c+1]//top of block
           + g1[r][c-1]+g1[r][c+1]               //middle of block
           + g1[r][c]+g1[r][c]+g1[r][c]<2        //bottom of block
            g1[r-1][c-1]+g1[r-1][c]+g1[r-1][c+1] //top of block
            + g1[r][c-1]+g1[r][c+1]                //middle of block
            + g1[r+1][c-1]+g1[r+1][c]+g1[r+1][c+1]>3) // bottom
    //copy to second array

  2. #2
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    The edge of the known universe
    Well how about a nice and simple
    for(int r=0;r<22;r++) {
        for(int c=0;c<22;c++) {
            neighbours = count_neighbours( g1, r, c );
            if ( neighbours == 2 || neighbours == 3 ) {
               // we're alive!
               g2[r][c] = 1;
            } else {
               // alas, poor Yorik
               g2[r][c] = 0;
    > g1[r-1][c-1]
    At r=0, c=0, this is way off the ends of the array
    You need to allow for this in your count_neighbours() function

    > while(g1[r][c]=1)
    You probably meant while(g1[r][c]==1)
    But I'm not sure that fixes anything.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
    Cheesy Poofs! PJYelton's Avatar
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    Sep 2002
    Also, I'm not sure what you are trying to accomplish with the while function. You should either kill the cell or keep it alive, but either way you don't need the while loop. With the algorithm that you have, if the cell is to be kept alive then it will just run into an infinite loop.

  4. #4
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    Jun 2003
    Yeah, I noticed, I changed it to an if statement and that seemed to work.. thanks for the help

  5. #5
    Its not rocket science vasanth's Avatar
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    Jan 2002
    hmm.. had done this beofre.. this might help you

    Check out my LIFE!

  6. #6
    Registered User major_small's Avatar
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    May 2003
    so have I... (it's called 'Life', Ironically ) I don't think I have my code there, but those are all open-source, so just post here or PM me if you need/want my code...

    P.S. - In my code, there's a problem writing back to the array so it kinda wraps around one or two columns... I just haven't gotten around to finding the problem...
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