Thread: Need help with small program to calculate a salary

Hi,

This program must used a while loop to calculate a salesperson's grosse income for one week.
The output has to looklike this -


Enter sales in dollars ( -1 to end ): 5000.00
Salary is: $650.00

Enter sales in dollars ( -1 to end ): 6000.00
Salary is: $740.00

Enter sales in dollars( -1 to end ): -1


My program doesn't display the salary when Iv'e inputted the sales.
Can anyone give me some advice please?

Code:

#include<iostream>
#include<conio>
using namespace std;

int main(int argc, char* argv[])
{
   double   sales1;
   double   sales2;
   double   salary;
   double   fixed = 200;


   cout << "Enter sales in dollars ( -1 to end ): " << endl;
   cin >> sales1;

   while( sales1 != -1 ) {
     sales2 = sales1 / 100 * 9;
     salary = sales2 + fixed;
   }

      if( salary != -1 ) {
         cout << "Salary is: " << salary;
      }

   getch();
   return 0;
}

For example, a person who sells $5000 worth of chemicals in a week receives $200 plus 9 percent of $5000, or a total of $650.

So I was thinking that the salesperson enters their sales as sales1. that's then read in.
sales1 then goes into a calculation that is stored in sales2. this calulates who much pay the salesperson gets by dividing by 100 times 9. then add this(sales2) to fixed($200) which is what each person gets per week, and store it in salary.

When I input 5000 for example, the cursor just moves to the next line without displaying something.

And one more thing, does the if statement really need to be there?

Thanks for any further advice.

Hi Salem

Thanks for your advice. But alas, it still doesn't output anything. What your'e solution did was when I inputed 5000.00 fo example and pressed enter, it just asked for input again, not displaying "Salary is: 650"
Iv'e set sales1, sales2, salary all to zero, but that didn't do the trick either.
Any other ideas?

Thanks

I must have been really tired not to have seen that mistake

But anyway, that didn't do the trick either. What could be missing that could make such a little program work

Code:

#include<iostream>
#include<conio>
using namespace std;

int main(int argc, char* argv[])
{
   double   sales1;
   double   sales2;
   double   salary;
   double   fixed = 200;


   cout << "Enter sales in dollars ( -1 to end ): " << endl;
   cin >> sales1;

   while( sales1 != -1 ) {
     sales2 = sales1 / 100 * 9;
     salary = sales2 + fixed;
   }

      if( sales1 != -1 ) {
         cout << "Salary is: " << salary;
      }

   getch();
   return 0;
}

Take a look at the minor differences between your code and this:

Code:

#include<iostream>
using namespace std;

int main()
{
   double   sales1;
   double   sales2;
   double   salary;
   double   fixed = 200;

   cout << "Enter sales in dollars ( -1 to end ): " << flush;
   cin >> sales1;

   while( sales1 != -1 ) {
     sales2 = sales1 / 100 * 9;
     salary = sales2 + fixed;
     cout << "Enter sales in dollars ( -1 to end ): " << flush;
     cin >> sales1;
   }

   cout << "Salary is: " << salary;

   cin.ignore();
   cin.get();
   return 0;
}

Well, I did this, and now it seems to run to specifications.
Thanks for your help anyway

Code:

#include<conio>
#include<iostream>
using namespace std;

int main()
{
   double   sales1;
   double   sales2;
   double   salary;
   double   fixed = 200;

   cout << "Enter sales in dollars ( -1 to end ): ";
   cin >> sales1;

   while( sales1 != -1 ) {
     sales2 = sales1 / 100 * 9;
     salary = sales2 + fixed;

     cout << "Salary is: " << salary << endl << endl;

     cout << "Enter sales in dollars ( -1 to end ): ";
     cin >> sales1;
   }

   getch();
   return 0;
}