1. ## wrong result?

Code:
```#include<iostream>
#include<conio.h>

using std::cout;
using std::cin;
using std::endl;

// functions prototypes

double Celsius( double );
double Fahrenheit( double );

int main()
{
// declare varibales

double tempCelsius, tempFahrenheit;

cout<< "Enter temperature in Celsius scale:";
cin>> tempCelsius;
cout<< "\nEnter temperature in Fahrenheit scale:";
cin>> tempFahrenheit;

// display results

cout<< "\n" << tempCelsius << "c = " << Celsius( tempFahrenheit ) << "F";
cout<< "\n" << tempFahrenheit << "F = " << Fahrenheit( tempCelsius ) << "c";

getch();
}

// definitions of Celsius() & Fahrenheit()

double Celsius( double valueA )
{
return (5/9)*(valueA-32);
}

double Fahrenheit( double valueB )
{
return (9/5)*valueB+32;
}```
This code gives the right answer for celsius temperature when converted from fahrenheit scale but centigrade scale to fahrenheit it gives only 0F as answer.

help needed/

2. >> (5/9)
Integer division.

gg

3. 5/9 = 0
5.0/9.0 = .5555555555555...

4. just a slight change makes it work.
only adding double or static_cast<double> doesn't give the required results on my dev c++ compiler.
y? is that?

Code:
```double Celsius( double valueA )
{
return (( double )(5.0/9.0)) *(valueA-32);
}
double Fahrenheit( double valueB )
{
return (( double )(9.0/5.0)) *valueB+32;
}```

5. Perhaps you should choose better names
double Celsius( double valueA )

Now is that to Celsius or from Celsius?
And valueA doesn't help. If it were either c or f for example, that might be more of a clue.

Code:
```#include<iostream>

using std::cout;
using std::cin;
using std::endl;

// functions prototypes
double Fahrenheit_to_Celsius( double f );
double Celsius_to_Fahrenheit( double c );

int main()
{
double c_to_f = Celsius_to_Fahrenheit( centigrade );   // convert it
double f_to_c = Fahrenheit_to_Celsius( c_to_f );       // and back again
cout << centigrade << " " << c_to_f << " " << f_to_c << endl;
}
}

// definitions of Celsius() & Fahrenheit()

double Fahrenheit_to_Celsius( double f )
{
double result = f - 32;
result = result * 5.0;
result = result / 9.0;
return result;
}

double Celsius_to_Fahrenheit( double c )
{
double result = c * 9.0;
result = result / 5.0;
result = result + 32;
return result;
}```

6. thanku salem