Initializing variables
I set a letter
char ch;
Int r;
and when I try to use them in an if-
cin >> ch;
if (ch==r)
cout << "blah blah blah"<<endl
every time I do this it gives me warning
warning C4700: local variable 'r' used without having been initialized
and the darn thing wont work, it just exits the program.
What do I do?
give r a value, say 65 or 92 or whatever.
int r = 65;
if(ch == r)
{...
r = 92;
if(ch == r)
{...
> local variable 'r' used
That's this line
> if (ch==r)
> without having been initialized
That's this line
> Int r;
Quite simple really, there is no assignment TO r before you try and read FROM r
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
i hope you are using
int
and not
Int
for one. (there is a difference).
But your warning is because you never set the value 'r' to anything.
You enter a character. Then you say if this character is equal to a value that I haven't even defined, output this.
If you initialized the value of r like
int r=0;
Your warning would go away. The thing is, you would never see your cout << "blah" because any character you enter will never be zero.
Examine this.
int main ()
{
char ch;
char other='A'; // note you can combine 'like' instantiations
cout << "Try to guess the letter: ";
cin >> ch;
if (ch==other)
cout << "YOU GUESSED IT!";
else
cout << "NOPE. TRY AGAIN!";
return 0;
}
Blue
I need to learn to type even faster...
Blue
