dynamic memory and arrays

[jomns]

I am learning c++
and a found an example on pointers and arrays:

..
int n;
cout << "Give an integer: \n" ;
cin >>n;

int *a;
a = new int[n];

..

My question is if it is possible to create a 2 dimensional array with pointers in order to create a board. I've tried:

... int h, w;

cout << "Give the high of the board \n";
cin >> h;
cout << "Give the width of the board \n";
cin >> l;

int *a;
a = new int[h][w];
...

But doing it like this gives me a lot of errors. What I'am trying to do is create a board of h by w with dynamic memory.

Does anybody knows how to do this?

Thanks anyway

[The Dog]

int h, w;

cout << "Give the high of the board \n";
cin >> h;
cout << "Give the width of the board \n";
cin >> l; //Could be the fact that you're using l instead of w

int *a;
a = new int[h][w];

If that's not the problem, then try using cin.ignore() after your first cin statement.

[jomns]

I am sorry that was typed wrong, what I meant was:

int h, w;
cout << "Give the high of the board \n";
cin >> h;
cout << "Give the width of the board \n";
cin >> w; 

int *a;
a = new int[h][w];

And I just cheked by compiling this and I still get the same errors.

Any suggestions?

Thanks,

Jonathan

[The Dog]

sorry, i didn't see what you were doing.

There are many threads about dynamic 2D arrays. Do a search and you will find many.

Here's some code for a 2D int array:

int **array;

int h, w, i;
cout << "Give the high of the board \n";
cin >> h;
cout << "Give the width of the board \n";
cin >> w; 

array = new int*[h];

for( i = 0; i < h; i++ )
{
     array[i] = new int[w];
}

//...
//Here you would use it
//...

for( i = 0; i < h; i++ )
{
     delete [] array[i];
}

delete [] array;

[jomns]

Thanks that was what I was looking for!