how can i do this without using loops?

[Guti14]

Hi,

I am supposed to print 4 lines of each like this

* * * * * * * *
* * * * * * * *

i have started like this

int main(int argc, char* argv[])
{

   cout << "* * * * * * * *\n";
   cout << " * * * * * * * *";

but what do i do now? i haven't covered loops in my book yet.

[SirCrono6]

You mean just make 4 lines of * * * * * * or whatever? Just use cout if you want:

#include <iostream>
using std::cin;
using std::cout;
using std::endl;
int main(int argc,char *argv[])
{
  cout<<"**********"<<endl;
  cout<<"**********"<<endl;
  cout<<"**********"<<endl;
  cout<<"**********"<<endl;
  cin.get();
  return 0;
}

That will print four lines of asterisks and not close. But you can do it with a loop.

[Epo]

If I understand right, you're trying to display 4 lines of stars?

If so, the easy way around would be close to what you have, but instead:

cout << "* * * * * * * *\n";
cout << "* * * * * * * *\n";
cout << "* * * * * * * *\n";
cout << "* * * * * * * *\n"; //You probably want this last '\n' character incase you want to display more things afterwards.

Using loops though, you could use something like:

int x;
for (x=0; x<4; x++)
{
cout << "* * * * * * * *\n";
}

What this does, is:
1) a variable "x" is set to 0
2) The "For Loop" (that's what it's called) will continue to go as long as x is less than 4
3) "x++" is short for "x = x + 1", so, x will go up by one each time
So, everything within the {} brackets goes, then x goes up by one, then the For Loop checks to see if it should stop yet, if not, it does the code in the {} brackets again, and so on, until x gets bigger than 4

Another loop method could be:

int x=0;
while(x < 4)
{
cout << "* * * * * * * *\n";
x++;
}

This will give you the same thing. x starts at 0. Then it displays your first line of stars. Then it increments x by 1. Then it checks to see if x is less than 4. If it is, it repeats the code in the {} brackets. If not, it will leave the loop.

I hope this helps out some.

[edit]
I'm not up to speed in my COUT stuff, so SirCrono's example will probably be better to follow.
[/edit]

[Guti14]

Sorry if i was unclear, well here goes -

the instructions - display the checkerboard pattern with 8 output statements. so that is like this

  cout << "* * * * * * * *\n";
  cout << " * * * * * * * *\n";
  cout << "* * * * * * * *\n";
  cout << " * * * * * * * *\n";
  cout << "* * * * * * * *\n";
  cout << " * * * * * * * *\n";
  cout << "* * * * * * * *\n";
  cout << " * * * * * * * *\n";

but then i have to display the same pattern using as few output statements as possible.

so i'm wondering how i could do that, without using a loop remember.

thanks

[Codeplug]

One statement.

cout << "* * * * * * * *\n"
     << " * * * * * * * *\n"
     << "* * * * * * * *\n"
     << " * * * * * * * *\n"
     << "* * * * * * * *\n"
     << " * * * * * * * *\n"
     << "* * * * * * * *\n"
     << " * * * * * * * *\n";

gg

[Salem]

  char *rows[] = {
    "* * * * * * * *\n",
    " * * * * * * * *\n"
  };
  cout << rows[0] << rows[1] << rows[0] << rows[1] << rows[0] << rows[1] << rows[0] << rows[1];

Disguised loop

void rowpair ( const char *rows[], int n ) {
    if ( n != 0 ) {
        cout << rows[0] << rows[1];
        rowpair( rows, n-1 );
    }
}

int main ( ) {
  char *rows[] = {
    "* * * * * * * *\n",
    " * * * * * * * *\n"
  };
  rowpair( rows, 4 );
}