how can i do this without using loops?

This is a discussion on how can i do this without using loops? within the C++ Programming forums, part of the General Programming Boards category; Hi, I am supposed to print 4 lines of each like this * * * * * * * * ...

  1. #1
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    how can i do this without using loops?

    Hi,

    I am supposed to print 4 lines of each like this

    * * * * * * * *
    * * * * * * * *

    i have started like this
    Code:
    int main(int argc, char* argv[])
    {
    
       cout << "* * * * * * * *\n";
       cout << " * * * * * * * *";
    but what do i do now? i haven't covered loops in my book yet.

  2. #2
    Rabite SirCrono6's Avatar
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    Question Uh...

    You mean just make 4 lines of * * * * * * or whatever? Just use cout if you want:

    Code:
    #include <iostream>
    using std::cin;
    using std::cout;
    using std::endl;
    int main(int argc,char *argv[])
    {
      cout<<"**********"<<endl;
      cout<<"**********"<<endl;
      cout<<"**********"<<endl;
      cout<<"**********"<<endl;
      cin.get();
      return 0;
    }
    That will print four lines of asterisks and not close. But you can do it with a loop.
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  3. #3
    Epo
    Epo is offline
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    If I understand right, you're trying to display 4 lines of stars?

    If so, the easy way around would be close to what you have, but instead:
    Code:
    cout << "* * * * * * * *\n";
    cout << "* * * * * * * *\n";
    cout << "* * * * * * * *\n";
    cout << "* * * * * * * *\n"; //You probably want this last '\n' character incase you want to display more things afterwards.
    Using loops though, you could use something like:
    Code:
    int x;
    for (x=0; x<4; x++)
    {
    cout << "* * * * * * * *\n";
    }
    What this does, is:
    1) a variable "x" is set to 0
    2) The "For Loop" (that's what it's called) will continue to go as long as x is less than 4
    3) "x++" is short for "x = x + 1", so, x will go up by one each time
    So, everything within the {} brackets goes, then x goes up by one, then the For Loop checks to see if it should stop yet, if not, it does the code in the {} brackets again, and so on, until x gets bigger than 4

    Another loop method could be:
    Code:
    int x=0;
    while(x < 4)
    {
    cout << "* * * * * * * *\n";
    x++;
    }
    This will give you the same thing. x starts at 0. Then it displays your first line of stars. Then it increments x by 1. Then it checks to see if x is less than 4. If it is, it repeats the code in the {} brackets. If not, it will leave the loop.

    I hope this helps out some.

    [edit]
    I'm not up to speed in my COUT stuff, so SirCrono's example will probably be better to follow.
    [/edit]
    Last edited by Epo; 12-20-2003 at 08:31 PM.

  4. #4
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    Sorry if i was unclear, well here goes -

    the instructions - display the checkerboard pattern with 8 output statements. so that is like this

    Code:
      cout << "* * * * * * * *\n";
      cout << " * * * * * * * *\n";
      cout << "* * * * * * * *\n";
      cout << " * * * * * * * *\n";
      cout << "* * * * * * * *\n";
      cout << " * * * * * * * *\n";
      cout << "* * * * * * * *\n";
      cout << " * * * * * * * *\n";
    but then i have to display the same pattern using as few output statements as possible.

    so i'm wondering how i could do that, without using a loop remember.

    thanks
    Last edited by Guti14; 12-20-2003 at 08:58 PM.

  5. #5
    Registered User Codeplug's Avatar
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    One statement.
    Code:
    cout << "* * * * * * * *\n"
         << " * * * * * * * *\n"
         << "* * * * * * * *\n"
         << " * * * * * * * *\n"
         << "* * * * * * * *\n"
         << " * * * * * * * *\n"
         << "* * * * * * * *\n"
         << " * * * * * * * *\n";
    gg

  6. #6
    and the hat of wrongness Salem's Avatar
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    Code:
      char *rows[] = {
        "* * * * * * * *\n",
        " * * * * * * * *\n"
      };
      cout << rows[0] << rows[1] << rows[0] << rows[1] << rows[0] << rows[1] << rows[0] << rows[1];

    Disguised loop
    Code:
    void rowpair ( const char *rows[], int n ) {
        if ( n != 0 ) {
            cout << rows[0] << rows[1];
            rowpair( rows, n-1 );
        }
    }
    
    int main ( ) {
      char *rows[] = {
        "* * * * * * * *\n",
        " * * * * * * * *\n"
      };
      rowpair( rows, 4 );
    }
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