Need some help with arrays and pointers

Can anyone help me with this code?

My desired output is:

String 1 = String1Text
*PointerStr1 = s + t + r + i + n + g + 1 + t + e + x + t

I appreciate any and all of your help! Thankyou in advance!

Here is my code:

Code:

#include <iostream> 

using namespace std; 

int main() 
{ 

char string1[] = "Hello World"; 
char *ptr; 
char ptr; 

cout << "The character string that you inititalized is : " << string1 << endl; 



for (int i = 0; *ptr + 1 !=('\0'); ++ i) 

if ((*ptr +1) == '\0') 
cout << *ptr; 
else 
{ cout << *ptr 
    << '+'; 
} 

cout << "The  string that is output : " << *ptr << endl; 


return 0; 

}

first of all you can't have two variables with the same name. first you declare char * ptr, and then char ptr;

second, what is the for loop for? make the pointer point to the address of the first element of the array; it is as simple as that.

Try this.

Code:

#include <iostream>

using namespace std;

int main() 
{ 

char string1[] = "Hello World"; 
char *ptr;

cout << "The character string that you inititalized is : " << string1 << endl;

for (ptr = string1; *ptr !='\0'; ++ptr)

if (*(ptr + 1) == '\0')
cout << *ptr; 
else 
{ cout << *ptr 
    << '+'; 
} 

return 0; 

}

I am supposed to initialize a character string to a text phrase and then write a function to traverse the contents of the string, using pointer-offset notation and then print each character seperated by the '+' sign.

I started by having just one character initialization to a pointer. And I also had the pointer equal the string but continuously received errors. And then I added the char ptr; to see if that would offset some errors. No avail.

Swoopy - I will definately try that out - Thanks!

you guys are AWESOME- perfect output and the desired results.

this site rocks

I see, but I think you are missunderstanding the concept of a pointer. A pointer is not a variable; you cannot store a value in a pointer.

so what you had in your original post: *PointerStr1 = s + t + r + i + n + g + 1 + t + e + x + t , can't be done. You set a pointer to point to an address of something else allready in the memory.

Axon - I think I am beginning to understand what a pointer does. I originally tried to declare string1=*ptr; but later revamped the code because I thought I coded that wrong in the declaration statement.

I should have made the original post clearer to what exactly I was looking for.

When I said "desired output" I wanted that desired output on the screen after the program was compiled. So, I should have better written my original problem better.

I am sorry for the confusion.

And thankyou again for all your help.

Or here's a second way.

Code:

#include <iostream>

using namespace std;

int main() 
{ 

char string1[] = "Hello World"; 
char *ptr;

cout << "The character string that you inititalized is : " << string1 << endl;

for (ptr=string1; *(ptr+1) !='\0'; ++ptr)
{
   cout << *ptr << '+'; 
} 
cout << *ptr;

return 0; 

}