Hi
There's something bothering me with my code, and I'm not sure what variable type to use as a result. I have this in my code:
My question is, will x be a double or an integer?Code:double x; int y; int z; x = y/z
Hi
There's something bothering me with my code, and I'm not sure what variable type to use as a result. I have this in my code:
My question is, will x be a double or an integer?Code:double x; int y; int z; x = y/z
>My question is, will x be a double or an integer?
x will be a double, but the value will lack any fractional part because y / z uses integer arithmetic. To get the fractional part, use C++'s type conversion rules and cast one of the operands to double:
Code:x = static_cast<double> ( y ) / z;
My best code is written with the delete key.
I've seen different syntax somewhere - will this work as well: (float) y?
> will this work as well: (float) y?
That's a 'C' style cast, which C++ supports for the moment.
The static cast Prelude showed is the preferred way for C++
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
>will this work as well: (float) y?
It will, but since you're assigning to a double variable, (double)y would be better. Or you could cast z instead of y, or both. It really doesn't matter since if either operand is double, the result of the expression is double. Also see Salem's comment on C-style casting.
My best code is written with the delete key.
