Arrays

This is a discussion on Arrays within the C++ Programming forums, part of the General Programming Boards category; Just a quick question about multidemintional arrays, i understand that when i create them i can put values into them ...

  1. #1
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    Arrays

    Just a quick question about multidemintional arrays, i understand that when i create them i can put values into them with = {values} however is there anyway to put the values in them the sameway after ive created them (without a loop of somekind)?

    Heres the code ive got, FONTHEIGHT and FONTWIDTH are #defines of 8 and 4. chr is just an int.
    Code:
             int FontArray[FONTHEIGHT][FONTWIDTH];
    	switch (chr)
    	{
    		// H
    	case 72: FontArray[][] = { {1, 0, 0, 1 }, 
    					      {1, 0, 0, 1 }, 
    					      {1, 0, 0, 1 }, 
    					      {1, 1, 1, 1 },
    					      {1, 1, 1, 1 },
    					      {1, 0, 0, 1 },
    					      {1, 0, 0, 1 },
    					      {1, 0, 0, 1 }}; break;
    	default: FontArray[][] = { {1, 1, 1, 1 }, 
    					     {1, 1, 1, 1 }, 
    					     {1, 0, 0, 1 }, 
    					     {1, 0, 0, 1 },
    					     {1, 0, 0, 1 },
    					     {1, 0, 0, 1 },
    					     {1, 0, 0, 1 },
    					     {1, 1, 1, 1 }}; break;
    	}

  2. #2
    S Sang-drax's Avatar
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    Re: Arrays

    Originally posted by H3g3m0n
    however is there anyway to put the values in them the sameway after ive created them (without a loop of somekind)?
    No.
    Last edited by Sang-drax : Tomorrow at 02:21 AM. Reason: Time travelling

  3. #3
    and the hat of wrongness Salem's Avatar
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    You could always use pointers...
    Code:
    #include <stdio.h> 
    #include <stdlib.h>
    
    #define FONTHEIGHT 8
    #define FONTWIDTH  4
    
    int main ( int argc, char *argv[] ) {
      int FontArrays[2][FONTHEIGHT][FONTWIDTH] = {
        {
          {1, 0, 0, 1 }, 
          {1, 0, 0, 1 }, 
          {1, 0, 0, 1 }, 
          {1, 1, 1, 1 },
          {1, 1, 1, 1 },
          {1, 0, 0, 1 },
          {1, 0, 0, 1 },
          {1, 0, 0, 1 }
        },
        {
          {1, 1, 1, 1 }, 
          {1, 1, 1, 1 }, 
          {1, 0, 0, 1 }, 
          {1, 0, 0, 1 },
          {1, 0, 0, 1 },
          {1, 0, 0, 1 },
          {1, 0, 0, 1 },
          {1, 1, 1, 1 }
        },
      };
      int r, c;
      int chr = 72;
      int (*fontptr)[FONTWIDTH];
      switch (chr)
      {
          case 72: fontptr = FontArrays[0]; break;
          default: fontptr = FontArrays[1]; break;
      }
      for ( r = 0 ; r < FONTHEIGHT ; r++ ) {
        for ( c = 0 ; c < FONTWIDTH ; c++ ) {
          printf( "%d", fontptr[r][c] );
        }
        printf( "\n" );
      }
      return 0;
    }
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  4. #4
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    Thanks, I guess ill probally have to find some otherway of retreving them, pointers probally wouldn't work as i would need atleast although many numbers would be returning the same array.

  5. #5
    and the hat of wrongness Salem's Avatar
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    > although many numbers would be returning the same array.
    Like

    case 72: case 73: case 74: case 75: fontptr = FontArrays[0]; break;

    In fact, why not just go for it and say
    fontptr = FontArrays[chr];
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

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