Boolean in a character array

This is a discussion on Boolean in a character array within the C++ Programming forums, part of the General Programming Boards category; Hi I am trying to get the code below displayed as X values where true, and O where false... so ...

  1. #1
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    Boolean in a character array

    Hi
    I am trying to get the code below displayed as X values where true, and O where false... so for the character array below, im trying to get it to output
    X X X
    X X O

    I have tried a few things such as a for loop (which i think is used?) but it ends up outputting something stupid



    Code:
    char Board[3][3] =	{ {true,true,true},  
    		  {true,true,false},};

  2. #2
    Registered User Codeplug's Avatar
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    I have tried a few things...
    Let's see em and we'll go from there.

    gg

  3. #3
    Toaster Zach L.'s Avatar
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    Think about the data type of 'true' and 'false'.
    The word rap as it applies to music is the result of a peculiar phonological rule which has stripped the word of its initial voiceless velar stop.

  4. #4
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    Code:
    for (int q = 0; q < 2; q++)
    		{
    
    			for (int p = 0; p < 3; p++)
    			{
    				if (Board[q][p] = true)
    				{
    				Board[q][p] = 'X';
    				cout << Board[q][p];
    				}
    		
    				if (Board[q][p] = false)
    				{
    					Board[q][p] = 'O';
    					cout << Board[q][p];
    				}
    			}
    			 cout << endl;
    		}
    Thats the closest ive got but i dont think its close to being correct as it just displays:
    XXX
    XXX
    when im trying to get
    XXX
    XXO (As the bottom right is false)

  5. #5
    The Defective GRAPE Lurker's Avatar
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    The char type cannot hold true and false values, learn more about data types.
    Do not make direct eye contact with me.

  6. #6
    Guest Sebastiani's Avatar
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    First problem:

    if (Board[q][p] = true)

    should be:

    if (Board[q][p] == true)

    >> for (int q = 0; q < 2; q++)

    should be:


    >> for (int q = 0; q < 3; q++)

    Finally, you could save yourself all of those steps by simply doing:

    Code:
    #define SET 'X'
    #define UNSET 'O'
    
    
     char Board[3][3] =
    {
      {SET, SET, SET},
      {SET, SET, SET},
      {SET, SET, UNSET}
    };
    Code:
    bool fun(bool value)
    {
        return std::pow(std::exp(1), std::complex<float>(0, 1) 
        * std::complex<float>(std::atan(1)*(1 << (value + 2))))
        .real() > 0;
    }

  7. #7
    Toaster Zach L.'s Avatar
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    For good programming practice, that really ought to be:
    const char SET = 'X';
    const char UNSET = 'O';
    The word rap as it applies to music is the result of a peculiar phonological rule which has stripped the word of its initial voiceless velar stop.

  8. #8
    Registered User
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    thanks alot
    sorted

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