Thread: Converting the format of dates

My program has a vector of 50 objects like this :

Code:

trans.push_back(Transaction(1365,"Norwich","20030901","1200",12,005,"Nobody present"));

What I need to do is convert all the dates from their current format (eg 20030901) to the standard UK date format eg 01/09/2003). I also need all the times to include a colon (eg 12:00).

How can I go about this?

Thanks.

It looks like you are sending the date and time to the Transaction constructor as strings.

Inside of that constructor, you could just use regular string manipulation functions to pick out the details and rearrange them into the member variables that store the string.

For example:

Code:

#include <iostream>
#include <string>

int main()
{
    std::string dateString = "20030901";

    if (dateString.length() < 8)
    {
        std::cerr << "oops, bad date string." << std::endl;
        return 1;
    }
    std::string yearString = dateString.substr(0, 4);
    std::string monthString = dateString.substr(4, 2);
    std::string dayString = dateString.substr(6, 2);

    std::cout << dayString << "/" << monthString << "/" << yearString << std::endl;
    return 0;
}