Help with parralell array of objects

**ForlornOdium** · 09-24-2003

ok, i was almost positive that there was nothing wrong with this code and everything, but when i compile it i get a lot of errors that i know are wrong. does anybody know if there are some stupid mistakes im overlooking or anything?

Code:

#include<iostream.h>


class Shipping
{
	public:
		double rate;
		char code;
};

void main()
{
	int x;
	char method
	Shipping info;
	char info[3].code = {'a', 't', 'r', 'h'};
	double info[3].rate={14.95, 10.25, 8.75, 25.99};
	cout<<"Please enter a shipping method code: ";
	cin>>method;
	for(x=0; x<4; ++x)
	{
		if( method==info[x].code)
			cout<<"The rate for your shipping method is $"<<info[x].rate;
		if(x=4)
			cout<<"You have entered an incorrect shipping method";
	}
}

thanks ahead of time for any help given.

**velius** · 09-24-2003

First you forgot a semi-colon(

on line 3 of the main() function.
Second you declared Shipping info then you redefined info to be an array of char then tried to access a member in the Shipping class with the member operator .
Third the rest of the problems seem to stem from the second problem above.

**ForlornOdium** · 09-24-2003

thanks! fixed every problem....except now i have one error and i dont have a clue what it means. on the line under the void main() statement, it has an error that says "error C2447: missing function header (old-style formal list?)"

**velius** · 09-24-2003

That usually means a syntax error. It could be that it looks like a function to the compiler. Verify your syntax.

**ForlornOdium** · 09-24-2003

wait...i put the semi colon in the wrong spot...i'm still getting all these errors! it says im missing a semi colon before the '.' in info[3].code and just about every other non-numeric/alphabetical character.

**velius** · 09-24-2003

Post your revised code please.

**ForlornOdium** · 09-24-2003

Code:

#include<iostream.h>


class Shipping
{
	public:
		double rate;
		char code;
};

void main()
{
	int x;
	char method;
	Shipping info[3];
	char info[3].code = {'a', 't', 'r', 'h'};
	double info[3].rate={14.95, 10.25, 8.75, 25.99};
	cout<<"Please enter a shipping method code: ";
	cin>>method;
	for(x=0; x<4; ++x)
	{
		if( method==info[x].code)
			cout<<"The rate for your shipping method is $"<<info[x].rate;
		if(x=4)
			cout<<"You have entered an incorrect shipping method";
	}
}

**velius** · 09-24-2003

Remove the char.
You cannot initialize an array of objects like that. You must do each one seperatly.
You have reservered space for only 3 you seem to want 4, but you want to initialize only the 4 one that does not exist.

**velius** · 09-24-2003

Do the same with the double and the initialization of rate.

**velius** · 09-24-2003

Here is the revised code.
I don't guarantee it works, just compiles.

Code:

#include<iostream.h>

class Shipping
{
public:
	double rate;
	char code;
};
int main(int argc, char** argv)
{
	int x;
	char method;
	Shipping info[4];
	
	info[0].code = 'a';
	info[1].code = 't';
	info[2].code = 'r';
	info[3].code = 'h';

	info[0].rate = 14.95;
	info[1].rate = 10.25;
	info[2].rate =  8.75; 
	info[3].rate = 25.99;
	cout<<"Please enter a shipping method code: ";
	cin>>method;
	
	for(x=0; x<4; ++x)
	{
		if( method==info[x].code)
			cout<<"The rate for your shipping method is $"<<info[x].rate;
		if(x==4) // you had x = 4 that is assignment
			cout<<"You have entered an incorrect shipping method";
	}
	return 0; // indicate sucess
}

**ForlornOdium** · 09-24-2003

thanks for the help!

**velius** · 09-24-2003

No problem. One more thing though, never use void main() always use int main(int argc, char** argv). If you don't understand why, you will once you get a good grasp on programming.

**Hunter2** · 09-24-2003

always use int main(int argc, char** argv)

Or int main(). The problem with void was that other programs might check its return value. I don't believe that the using the arguments is necessary.

Help with parralell array of objects

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