Java Problem

This is a discussion on Java Problem within the C++ Programming forums, part of the General Programming Boards category; Hi, I need to do the following... A positive number P is a triangular number if there exists a number ...

  1. #1
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    Nov 2001
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    Java Problem

    Hi,

    I need to do the following...

    A positive number P is a triangular number if there exists a number n such that P=1+2+3++n. That is, P is the sum of the numbers from 1 to n.

    For example, 6 is a triangular number as 6=1+2+3. Also, 28 is a triangular number as 28=1+2+3+4+5+6+7. However, 7 is not a triangular number. The number 20 is also not a triangular number.

    Write a program that will prompt for a positive integer. After a number is entered, the program will determine and print if the number is a triangular or not. If it is triangular , also print the range of numbers that the number is the sum of. Your program will continue reading in numbers and processing them until a non-positive number is read in.

    Your output should look something like (the spacing need not be exact):

    Enter a positive number (<= 0 to quit): 6

    The number 6 is triangular. It is the sum from 1 to 3.

    Enter a positive number (<= 0 to quit): 1000

    The number 1000 is not triangular.

    Enter a positive number (<= 0 to quit): 8128

    The number 8128 is triangular. It is the sum from 1 to 127.

    Enter a positive number (<= 0 to quit): 33550336

    The number 33550336 is triangular. It is the sum from 1 to 8191.

    Enter a positive number (<= 0 to quit): -1

    End of Processing.


    So far I got this... Which is for a Perfect Number program. What parameters do I need to change in here so that I can make the above program work?


    public class Triangle {
    public static void main (String [] args) {
    ConsoleReader console = new ConsoleReader (System.in);

    int number; //Number to be calculated
    int divisors; //To check sum of divisors
    int sum; //Sum
    int i;

    while(true) {

    System.out.print("Enter a positive number (<= 0 to quit): ");
    number = console.readInt();

    System.out.println();
    if (number <= 0)
    System.exit(0);

    sum = 0;
    for (i = 1; i < number - 1; i = i + 1) {
    if (number % i == 0)
    sum = sum + i;
    }

    divisors = sum;

    if (number == divisors)
    System.out.println("The value " + number + " is PERFECT");
    else
    System.out.println("The number " + number + " is NOT PERFECT");

    System.out.println();

    }
    }
    }


    Thanks in advance!

    P.S I've been browsing this site for some time now, and I must say it is the best site on programming out there! Keep up the good work guys!

  2. #2
    and the hat of wrongness Salem's Avatar
    Join Date
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    Well you've obvously not figured out that this isn't a Java site.

    This is C/C++/C# - not Java.

    > and I must say it is the best site on programming out there
    Still isn't Java though....

    http://www.programmersheaven.com/oth...sageBoards.htm
    has a Java board, maybe they can help.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
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  3. #3
    Registered User
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    Ok, thanks.

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